What is the answer to > solve 4cos (theta/3) -2 = 0, over [0, 4pi)
1 answer:
You might be interested in
Answer:
A'(-2, 1), B'(1, 0), C'(-1, 0)
Step-by-step explanation:
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.
If a point X(x, y) is translated a units right and b units down, the new location is X'(x + a, y + b) whereas if a point X(x, y) is translated a units left and b units up, the new location is X'(x - a, y - b).
If a point X(x, y) is rotated 90° clockwise about the origin, the new location is X'(y, -x)
From the image attached, ∆ABC is at A(0, 0), B(1,3) C(1, 1)
If ∆ABC is translated 2 units down and 1 unit to the left (x - 1, y - 2), the vertices would be A*(-1, -2), B*(0, 1), C*(0, -1)
If it is then rotated 90° clockwise about the origin, the new location is A'(-2, 1), B'(1, 0), C'(-1, 0)
