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Pavel [41]
3 years ago
14

Find the value of x. A. 39 B. 21 C. 40 D. 119

Mathematics
1 answer:
True [87]3 years ago
7 0

Answer:

the answer is D 119

hope it helps!

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cms

Step-by-step explanation: multiply 20x160934

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247 is the correct answer!

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Which best describes the difference of 17,552 –14,564?
Alenkasestr [34]

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2988

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3 years ago
A right triangle has legs of length 4x and 20x. What is an expression for the hypotenuse of the right triangle
kherson [118]

Answer:

4x\sqrt{26}.

Step-by-step explanation:

Given information:

Leg_1=4x

Leg_2=20x

According to the Pythagoras theorem,

(hypotenuse)^2=(Leg_1)^2+(leg_2)^2

Using Pythagoras theorem, we get

(hypotenuse)^2=(4x)^2+(20x)^2

(hypotenuse)^2=16x^2+400x^2

(hypotenuse)^2=416x^2

Taking square root on both sides.

hypotenuse=\sqrt{416x^2}

hypotenuse=4x\sqrt{26}

Hence, the expression of the hypotenuse is 4x\sqrt{26}.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
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