The Sears tower in Chicago is 1,454 feet tall. Write the height as an integer

How much will it cost for him to buy 3 dozen using the rate $12.00 for 20 cookies?

Art [367]

3 dozen = 36 cookies

20/12 = 1.666666666666667

1.666666666666667 = 1 cookie

(x36)

36 x 1.666666666666667 = 60

It will cost him $60 for 3 dozen cookies

4 0

3 years ago

What is the box-and-whiskers plot used to show?

Ad libitum [116K]

Answer:

c. median

Step-by-step:

it shows you the numbers you got the most with the box and the whiskers are the outliers.

3 0

3 years ago

Read 2 more answers

Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or

Aleks04 [339]

Answer:

a) $\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)$

b) Since the sample size is large enough n>30 and the original distribution for the random variable X doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) $P(\bar X \leq 77)=P(Z$

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

$E(X) = 75$

$sd(X) = 7$

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is also normal and is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)$

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

$z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}$

And we want to find this probability:

$P(\bar X \leq 77)=P(Z$

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0

3 years ago

In △PKQ, PK = KQ = 12, m∠P = 35º. Find PQ.

Neporo4naja [7]

The length of PQ is 19.66 units

Step-by-step explanation:

The given is:

1. PK = KQ = 12

2. m∠P = 35º

We need to find the length pf PQ

∵ PK = KQ

∴ m∠P = m∠Q

∵ m∠P = 35°

∴ m∠Q = 35°

The sum of measures of the angles of a triangle is 180°

∴ m∠P + m∠Q + m∠K = 180°

∴ 35 + 35 + m∠K = 180

∴ 70 + m∠K = 180

- Subtract 70 from both sides

∴ m∠K = 110°

Let us use cosine rule to find the length of PQ

∵ PQ = $\sqrt{(KP)^{2}+(KQ)^{2}-2(KP)(KQ)cos(K)}$

∵ PK = 12 , KQ = 12 , m∠K = 110°

- Substitute these values in the rule

∴ PQ = $\sqrt{(12)^{2}+(12)^{2}-2(12)(12)cos(110)}$

∴ PQ = 19.66

The length of PQ is 19.66 units

Learn more:

You can learn more about triangle in brainly.com/question/12985572

#LearnwithBrainly

4 0

3 years ago

Cameron tells about his trip to the Big Books store. "How awful!

kari74 [83]

The answer would be $19 on eg

4 0

3 years ago