The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
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Sum of two opposite angles in a Cyclic Quadiratral is 180°
Answer:
x = 7
y = 0
Step-by-step explanation:
Close, but not quite.
X=12.5
If the perimeter is 90
90=3x+3x+15
Combine like terms
90=6x+15
Subtracts 15 from both sides
75=6x
Divide by six to get x by itself
12.5=x
Does this help?
Answer:
E
Step-by-step explanation:
(X1, Y1) = (-3,-2)
(X2,Y2)=(4,8)
SLOPE= (Y2-Y1) / (X2-X1)
= (8-(-2)) / (4-(-3))
=(8+2) / (4+3)
= 10/7
Hope it was helpful
