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Nastasia [14]
4 years ago
6

Nick types 275 words in 2.5 minutes. At this rate, how many hours would it take for him to type 9900 words?

Mathematics
1 answer:
ioda4 years ago
5 0
3/5 of an hour (0.6 hours)



First, find how many words Nick types in an hour by multiplying 275 * 60.

Nick types 16,500 words per hour.

Now just divide 9,900 by 16,500.

It takes Nick 3/5 of an hour to type 9,900 words. (0.6 hours)



Please consider marking this answer as Brainliest to help me advance.

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Burka [1]

Answer:

$1954

Step-by-step explanation:

Given the profit function expressed as;

y=-3x^2 + 197x – 1279

The profit is at maximum when dy/dx = 0

dy/dx = -6x + 197

0 = -6x+197

6x = 197

x = 197/6

x = 32.83

substitute 32.83 into the modeled function

y=-3x^2 + 197x – 1279

y -3(32.83)²+197(32.83) - 1279

y = -3(1,078.03)+6,467.51 - 1279

y = -3,234.09+6,467.51-1279

y = 1,954.42

hence the maximum amount of profit the company can make, to the nearest dollar is $1954

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3 years ago
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uysha [10]

Answer:

A) 64 cm²

Step-by-step explanation:

Trapezoid area formula:

A=\frac{a+b}{2} h

Given:

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b = 10

h = 8

Work:

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5 0
3 years ago
The measure of angle R is 3 degrees less than twice the measure of angle S. If the sum of the measures of the two angles is 72 d
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2x-3+x=72
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3 0
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Which series is convergent? Check all that apply.
xxTIMURxx [149]

Answer:

The convergent series are;

\sum \limits _{n = 1}^\infty \left( \dfrac{1}{5} \right) ^n

(And)

\sum \limits _{n = 1}^\infty \left( \dfrac{1}{10} \right) ^n

Step-by-step explanation:

A series in mathematics is the sum of a sequence of numbers to infinity

A convergent series is a series that sums to a limit

From the given options, we have;

First option

\sum \limits _{n = 1}^\infty \dfrac{2\cdot n}{n + 1}

As 'n' increases, 2·n becomes more larger than n + 1, and the series diverges

Second option

\sum \limits _{n = 1}^\infty \dfrac{n^2 - 1}{n - 2}

As 'n' increases, n² - 1, becomes more larger than n - 2, and the series diverges

Third option

\sum \limits _{n = 1}^\infty \left( \dfrac{1}{5} \right) ^n

As 'n' increases, \left( \dfrac{1}{5} \right) ^n, becomes more smaller and tend to '0', therefore, the series converges

Fourth option

\sum \limits _{n = 1}^\infty \left( \dfrac{1}{10} \right) ^n

As 'n' increases, 3 \times\left( \dfrac{1}{10} \right) ^n, becomes more smaller and tend to '0', therefore, the series converges

Fifth option

\sum \limits _{n = 1}^\infty  \dfrac{1}{10} \cdot (3) ^n

As 'n' increases, \dfrac{1}{10} \cdot (3) ^n, becomes more larger and tend to infinity, therefore, the series diverges.

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3 years ago
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Alchen [17]

Answer:

91

Step-by-step explanation:

4 0
3 years ago
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