The least common multiple of 18 and 42 is 126. Sorry I don't know how to explain it.
Let , side lawn is a.
Area of boundary is :

Now, total cost is given by :

Area left is :

Price to empty space with turfs is :

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
136×25%=136×25/100= 3 400/100=34
so the markeup value is
136+34= 170
170×17%=170×17/100=2 890/100=28.9
170-28.9=141.1
Selling price=136+170=306
9514 1404 393
Answer:
- 238 gallons 7%
- 119 gallons 1%
Step-by-step explanation:
Let h represent the number of gallons of high butterfat content milk. Then 357-h will be the number of gallons of 1% milk. The total amount of butterfat in the mix is ...
0.07h +0.01(357 -h) = 0.05(357)
0.06h = 14.28 . . . . . . . . . . subtract 3.57, collect terms
h = 238 . . . . . . . . . . divide by 0.06
357-h = 357 -238 = 119
238 gallons of 7% and 119 gallons of 1% are needed.