hey let me tell you this you just never helped me and cheating is not good so yeah treat people the way you want to be treated and I saw your answers to other people it's not good to cheat just a piece of advice
Answer:
Q10 is 13.64 cm3
Q 11 is 221 cm3
Step-by-step explanation:
volume is cross sectional area times height for Q 10
volume is length times width times height for Q 11
Answer:
Yes
Step-by-step explanation:

Answer:
Average speed is 37.35 mi/h
Step-by-step explanation:
given data
leave = 34 minutes before
church distance = 12.0 miles
average speed first 17 minutes = 5.0 mi/h
solution
so we find Total distance travel in first 17 minutes = speed × time
Total distance travel in first 17 minutes = 5 × 
Total distance travel in first 17 minutes = 1.416 mi
and
Distance Remaining = 12 - 1.416 = 10.584 mi
Time Remaining = 34 - 17 min = 17 min
so
remaining distance Average speed =
Average speed =
Average speed is 37.35 mi/h
Answer:
y=-(x+3)^2
y=-x^2-6x-9
Step-by-step explanation:
i uh hope this is correct
hope thia helps <3