Using the greatest common factor for the terms, how can you write 56 + 32 as a product?

Suppose an astronaut can jump vertically with an initial velocity of 5 m/s. The time that it takes him to touch the ground is gi

Vitek1552 [10]

Answer:

$t=1.020s$

Step-by-step explanation:

Given Equation:

$5t-0.5at^{2} =0$

Actually the given equation is the 2nd equation of motion

i.e. $S =V_{i} t+0.5at^{2}$

where $S=0$ because the astronaut jumps on the earth

and initial velocity $V_{i}=5$

to find time $t$ , put the given value of $a=9.8m/s^{2}$ in the given equation, we get

$5t-0.5(9.8)t^{2} =0\\t(5-4.9t)=0\\ \ dividing\ both\ sides\ by\ t\ we \ get\\ 5-4.9t=0\\4.9t=5\\t=\frac{5}{4.9}\\ t=1.020s$

it will take $t=1.020s$ to reach the ground if he jumps on the Earth

3 0

3 years ago

Pls answer question 6 and 7

ra1l [238]

Answer:

go to the website slader.com

Step-by-step explanation:

it has most textbooks on it and the answers to textbook questions

8 0

3 years ago

PROVE THESE TRIANGLES ARE CONGRUENT

jenyasd209 [6]

Answer:

These triangles cannot be proved congruent

Step-by-step explanation:

The theorems for congruence are SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.

8 0

2 years ago

Read 2 more answers

It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha

stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

0.54% of the calls receive a busy signal, hence p = 0.0054.

A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

$P(X \geq 5) = 1 - P(X < 5)$

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009$

$P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062$

$P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218$

$P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513$

$P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903$

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295$

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0

2 years ago

Help please!<br><br> How do I graph f(x)=3/4x+2? What points do I plot?

mariarad [96]

(0, 2 ), (4,5)

to draw a graph of a straight line , we only require 2 points

select any 2 values for x, substitute them into the equation for the corresponding y- coordinates

x = 0 → y = 0+2 = 2 ⇒ (0, 2)

x = 4 → y = 3+2 = 5 ⇒ (4, 5)

Plot these 2 points and draw a straight line through them for graph

8 0

3 years ago

Read 2 more answers