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4 years ago

Find the product. (- d + 4)(- d - 4)

Mathematics

1 answer:

sashaice [31]4 years ago

3 0

The product is
(-d)^2 -4^2 = d^2 -16 . . . . . corresponds to the 2nd selection

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By definition, (fog)(x) = f(g(x))So if g(2) = 3 and f(3) = 16, then (fog)(2) =

marusya05 [52]

Answer:

$(f\circ g)(2)=16$

Step-by-step explanation:

By definition composite function would be:

$(f\circ g)(x)=f(g(x))$

Then, if g(2)=3 and f(3)=16, therefore for f(g(x)):

$\begin{gathered} (f\circ g)(x)=f(g(2))=f(3) \\ \text{Hence,} \\ (f\circ g)(2)=16 \end{gathered}$

6 0

1 year ago

Solve for x: x/2+1=5

Kamila [148]

Answer:

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Discuss the advantages and disadvantages of displaying data in a table and in a graph

gogolik [260]

Answer:

Step-by-step explanation:

6 0

2 years ago

What is the solution set of 2x(x - 1) = 3?

garik1379 [7]

First you must distribute the 2x to the numbers inside the parentheses

(2x * x) + (2x * -1) = 3

$2x^{2}$ - 2x = 3

To make this a quadratic equation you can solve bring the 3 over to the left side of the equation by subtracting it to both sides

$2x^{2}$ - 2x - 3 = 0

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

$ax^{2} +bx +c = 0$

That means that in this equation...

a = 2

b = -2

c = -3

^^^Plug these numbers into the quadratic equation and solve...

$\frac{2+/-\sqrt{(-2)^{2}-4(2)(-3)}}{2(2)}$

$\frac{2 +/-\sqrt{4+24}}{4}$

$\frac{2+/-\sqrt{28} }{4}$

$\frac{2+/-2\sqrt{7} }{4}$

$\frac{1+/-\sqrt{7} }{2}$

Keep in mind that +/- is ±

$\frac{1+\sqrt{7} }{2}$

$\frac{1-\sqrt{7} }{2}$

^^^Exact answers

Approximations:

1.823

-0.823

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0

3 years ago

Can someone please help me with this? I'd greatly appreciate it! Serious answers only please!

vampirchik [111]

First find the slope:
The slopes of perpendicular lines must multiply to -1.
-9m = -1 ----> m = 1/9

Next, use point-slope form:
y - y1 = m(x-x1) , where given point (0,5) is (x1,y1)
y - 5 = (1/9)(x - 0)

Finally, solve for y to put it in slope-intercept form:
y = (1/9)x + 5

6 0

3 years ago