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Norma-Jean [14]
3 years ago
12

The sum of two numbers is 74. The larger number is 3 more than the smaller number. Find the numbers.

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer: It's 35.5 and 38.5


Step-by-step explanation:

First, subtract 74 by 3  giving you 71.

Next, divide 71 by 2; it gives you 35.5 (that's your first number).

Then, add the 3 that you took away to 35.5 and get 38.5 (that's your second number).


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Step-by-step explanation:

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Sveta_85 [38]

Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

Z = -2.88

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use \mu = 47.4, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 47.4}{2.5}

Z = -0.96

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

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Answer:

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