Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
__
Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.
Answer:
g²/f⁷h
Step-by-step explanation:
Because f⁹-f²=f⁷ which leaves f⁷ on the bottom, g³-g=g² which leaves g² on the top, and h⁵-h⁴=h which leaves h on the bottom.
Answer:
2.6666666e+32
Step-by-step explanation:
1.add
2.multiply
3. you have your answer
Answer:
first one ig
Step-by-step explanation:
Answer:
I don't see anything
Step-by-step explanation:
