Answer:
Yes they will intersect
Function 1= F(X)=2X+5
Function 2=H(X)=3X+2
INTERSECT=(3,11)
Step-by-step explanation:
First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then
you replace the x for a number:
Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)
X=1----->Y=2+5=7 X=1------>Y=3·1+2=5
X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8
X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11
With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)
Answer:
31/2 pounds of ham
Step-by-step explanation:
times the denominator by the mixed number.
Answer:
.5
Step-by-step explanation:
.5 times 1/10 is .05. move the decimal over!
Answer:
The cost of chocolate pumpkins is $1.89, masks cost $5.75 and candy witches cost $1.62
Step-by-step explanation:
Let x represent the cost of chocolate pumpkins, y the cost of masks and z the cost of candy witches.
Cory shopping can be represented as:
3x + 4y + 8z = 41.63 (1)
Josh shopping can be represented as:
6x + 2y + 14z = 45.52 (2)
Dan shopping can be represented as:
8x + 3y + 25z = 72.87 (3)
The equations in matrix form is:
![\left[\begin{array}{ccc}3&4&8\\6&2&14\\8&3&25\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}41.63\\45.52\\72.87\end{array}\right] \\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}3&4&8\\6&2&14\\8&3&25\end{array}\right] ^{-1}\left[\begin{array}{c}41.63\\45.52\\72.87\end{array}\right] \\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}1.89\\5.75\\1.62\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%264%268%5C%5C6%262%2614%5C%5C8%263%2625%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D41.63%5C%5C45.52%5C%5C72.87%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%264%268%5C%5C6%262%2614%5C%5C8%263%2625%5Cend%7Barray%7D%5Cright%5D%20%5E%7B-1%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D41.63%5C%5C45.52%5C%5C72.87%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1.89%5C%5C5.75%5C%5C1.62%5Cend%7Barray%7D%5Cright%5D)
The cost of chocolate pumpkins is $1.89, masks cost $5.75 and candy witches cost $1.62
Answer:
9Kg, 18Kg and 63 Kg
Step-by-step explanation:
Sum the parts of the ratio, 1 + 2 + 7 = 10 parts
Divide the weight of sand by 10 to find the value of one part of the ratio
90 Kg ÷ 10 = 9 Kg ← value of 1 part of the ratio, thus
2 parts = 2 × 9 Kg = 18 Kg
7 parts = 7 × 9 Kg = 63 Kg
Thus the weights of each bag are 9 Kg, 18 Kg and 63 Kg
