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Ganezh [65]
2 years ago
7

Interest is compounded semianually. Find the amount in the account after the given time.

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
5 0

Answer:

5,630.81$

A = 5000(1 + (0.04 × 3)) = 5600

A = $5,630.81

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*20 pts*
Leno4ka [110]

a.      This is the geometric sequence: a1 = 1.5 m = 150 cm, r = 0.74

The formula now is an = a1 x r ^ n-1

 

Just substitute a1 = 150 cm and r = 0.74

an = 150 x (0.74) ^ n – 1

 

b.      The second part is:

A6 = 150 x 0.74 ^ 6-1

= 150 x 0.74 ^5

= 150 x 0.221906624

= 33.28509936 cm

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3 years ago
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M is between points C and Q. CM=17 and CQ=21. What is MQ?
katrin2010 [14]
Sometimes it helps to draw it out...

     (17)
C_______M_________Q
|___________________|
             21

therefore, CM + MQ = CQ
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MQ = 21 - 17
MQ = 4 <===
8 0
3 years ago
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Find the value of X to the nearest tenth:
castortr0y [4]

Answer:

13.0

Step-by-step explanation:

sin(65°) × 14.3 would give u 12.9 then u round it to the 13

5 0
2 years ago
8/(-4)+7<br><br><br><br> help LMFO <br> and explain
Vilka [71]

Answer:

5

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reminder of rules for division

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7 0
3 years ago
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Walter invests $100,000 in an account that compounds interest continuously and earns 12%. How long will it take for his money to
prohojiy [21]

Answer:

300000= 100000 e^{0.12 t}

We divide both sides by 100000 and we got:

3 = e^{0.12 t}

Now we can apply natural logs on both sides;

ln(3) = 0.12 t

And then the value of t would be:

t = \frac{ln(3)}{0.12}= 9.16 years

And rounded to the nearest tenth would be 9.2 years.

Step-by-step explanation:

For this case since we know that the interest is compounded continuously, then we can use the following formula:

A =P e^{rt}

Where A is the future value, P the present value , r the rate of interest in fraction and t the number of years.

For this case we know that P = 100000 and r =0.12 we want to triplicate this amount and that means A= 300000 and we want to find the value for t.

300000= 100000 e^{0.12 t}

We divide both sides by 100000 and we got:

3 = e^{0.12 t}

Now we can apply natural logs on both sides;

ln(3) = 0.12 t

And then the value of t would be:

t = \frac{ln(3)}{0.12}= 9.16 years

And rounded to the nearest tenth would be 9.2 years.

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3 years ago
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