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2 years ago

If a city with a population of 50,000 doubles in size every 16 years, what will the population be 32 years from now?

1 answer:

7 0

Pretty sure its 200,000 because, 16 goes into 32 twice and its doubles 50,000 every 16 years, so it would be 50,000 multiplied by 4 since it doubles . and that would give you 200,000. (it was hard explaining this)

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Wes is pouring some ketchup for his potato wedges. Is it reasonable to say that Wes will use 2 fluid ounces?

Step2247 [10]

Yes, 2 ounces is reasonable

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2 years ago

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What are some ways you can create a new system of equations based on a given system?

docker41 [41]

By adding/ subtraction systems

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2 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

Can someone help me with this

Morgarella [4.7K]

Answer:

FG=30

Step-by-step explanation:

Since we know that Point G is on the Segment FH, it doesn't really matter where G is, but we can know for certain that:

$FH=FG+GH$

We are given that FH is 4x, GH is x, and FG is 2x+10. Substitute:

$4x=(2x+10)+x$

Solve for x. On the right, combine like terms:

$4x=3x+10$

Subtract 3x from both sides:

$x=10$

So, the value of x is 10.

To find the value of FG, substitute 10 into its x:

$FG=2x+10\\FG=2(10)+10$

Multiply:

$FG=20+10$

Add:

$FG=30$

And we're done!

6 0

2 years ago

4. (03.03 HC)

Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

value of 8

relation : f(x) = 8x - 5....when x = 8

f(8) = 8(8) - 5

f(8) = 64 - 5

f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

19 = 8x - 5

19 + 5 = 8x

24 = 8x

24/8 = x

3 = x <==

7 0

2 years ago