Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
D) 30
Step-by-step explanation:
3(a + 4b)-6 = 3 ( 4 + 4*2) - 6
= 3( 4+8 ) - 6
= 3*12 - 6
= 36 - 6 =30
Note that there are 5 exams altogether: 4 hour exams and 1 final exam. Let the grade on the final be x.
The arith. mean of these 5 grades would be
<span>70+ 86+ 81 + 83 + x
</span> course grade = arith. mean = -------------------------------------
5
Answer:
384 ft
Step-by-step explanation:
d₁ = kₓt₁²
256 = kₓ4
k = 256/4 = 64
d₂ = kₓt₂² = 64ₓ6 = 384 ft
