Answer:
a) 4.9 s
b) 167.8 m
Explanation:
Hello!
To solve this question we need to make use of the equations of motion of both the motorcycle xm(t) and the car xc(t) at t=5
Let us consider the position of the motorcycle at t=5 as the origin, that is:
xm(t+5) = vt + (1/2)at^2
xc(t+5) = vt + 60 m
where v = 22.0m/s and a=5m/s^2
We are looking for the time t' when the position of the car and the motorcycle are the same:
xm(t'+5)=xc(t'+5)
vt' + (1/2)at'^2 = vt' +60m
t' = √(120 m /a) = 4.89898... s
Since we are considering the origin of the cooordinate system at the position when the motorcycle starts to accelerate, the distance travelled by the motorcycle until it catches the car is given by:
xm(t'+5)= vt' + (1/2)at'^2
xm(9.89898s) = (22 * 9.89898 + 2.5 * 9.89898^2)m
xm(9.89898s)= 167.777... m
I think it would be plum pudding, solid ball, solar system.
Answer:

Explanation:
The period of a simple pendulum is given by:

where
L is the length of the pendulum
g is the acceleration of gravity
From this equation we can write

Taking the square of this equation, we get:

So we see that
is proportional to L and inversely proportional to g. So, we can write:

So the only correct option is

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