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Delvig [45]
1 year ago
7

suppose you are hiking along a trail. make a comparison between the magnitude of your displacement and your distance traveled.

Physics
1 answer:
stellarik [79]1 year ago
8 0

The magnitude of your displacement can be less than your distance traveled And The magnitude of your displacement can be equal to your distance traveled.

Magnitude in physics is simply described as "distance or quantity." It shows the size or direction that an object moves in either an absolute or relative sense.  A force's magnitude is defined as the total amount of forces operating on an item. The strength of the force grows if every force is exerting itself in the same direction. The magnitude of the force diminishes when forces are applied to an object from various angles. Meters per second squared is the unit used to measure acceleration. The units must account for both variables since acceleration deals with both velocity and time. The object's current speed is represented by the magnitude of the velocity vector. The velocity vector is pointed in the same general direction as the object's motion. Multiply the constant acceleration rate by the time difference to determine the magnitude of the velocity at any given moment, and then add that value to the beginning velocity.

Learn more about Magnitude here:

brainly.com/question/28173919

#SPJ4

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Carl went on a Euro Trip and was traveling from Spain to Russia. When he looked on the map it said Russia was 7035 km away from
bija089 [108]

Answer:

The average speed would be 279.167 meters per second.

Explanation:

Speed ​​is the magnitude that expresses the variation in position of an object and as a function of time. In other words, speed is defined as the relationship established between the distance traveled and the time elapsed in the movement of a mobile.

Speed can be calculated using the following expression:

Speed=\frac{distance}{time}

In this case:

  • distance= 7,035 km
  • time= 7 hours

Since the required unit of speed is meter per second, then you convert from km to meters for the case of distance, and from hours to seconds for the case of time. So:

  • distance= 7,035 km= 7,035,000 m (being 1 km= 1,000 m)
  • time= 7 hours= 420 minutes= 25,200 seconds (being 1 hour=60 minutes and 1 minute=60 seconds)

Replacing in the definition of speed:

Speed=\frac{7,035,000 meters}{25,200 seconds}

Solving:

Speed=279.167\frac{meters}{ seconds}

Then, <u><em>the average speed would be 279.167 meters per second.</em></u>

3 0
3 years ago
________ is a measure of the particle size a stream can transport.
Over [174]
Is there any answers choices..?
7 0
3 years ago
Please tell the correct answer​
alukav5142 [94]

Answer:

The answer is C she didn't mark C so its your best best of trying.Good Luck!

8 0
3 years ago
A 55 kg track and field athlete has an average power output of 5.4 kW during the 200 meter dash. How quickly did she finish the
olga_2 [115]

The time taken for the athlete to finish the race is 20 s (Option A)

<h3>What is power? </h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = weight × distance

Therefore,

Power = (weight × distance ) / time

<h3>How to determine the time </h3>
  • Mass (m) = 55 Kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Weight = mg = 55 × 9.8 = 539 N
  • Power (P) = 5.4 KW = 5.4 × 1000 = 5400 W
  • Distance (d) = 200 m
  • Time (t) =?

Power = (weight × distance ) / time

5400 = (539 × 200) / t

5400 = 107800 / t

Cross multiply

5400 × t = 107800

Divide both side by 5400

t = 107800 / 5400

t = 20 s

Learn more about power:

brainly.com/question/5684937

#SPJ1

5 0
2 years ago
In a container of negligible mass, 0.400 kg of ice at an initial temperature of -29.0 ∘C is mixed with a mass m of water that ha
Pie

Answer:

1 kg

Explanation:

The container has negligible mass and no heat is loss to the surrounding.

Mass of ice = 0.4kg, initial temperature of ice = -29oC, final temperature of the mixture = 26oC, mass of water (m2) = ?kg, initial temperature of water = 80oC, c ( specific heat capacity of water ) = 4200J/kg.K, Lf = heat of fusion of water = 3.36 × 10^5 J/kg

Using the formula:

Quantity of heat gain by ice = Quantity of heat loss by water

Quantity of heat gain by ice = mass of ice × heat of fusion of ice + mass of water × specific heat capacity of water = (0.4 × 3.36 × 10^ 5) + (0.4 × 4200 × (26- (-29) = 13.44 × 10^4 + 9.24 × 10^ 4 = 22.68 × 10^4 J

Quantity of heat loss by water = m2cΔT

Quantity of heat loss by water = m2 ×4200× (80 - 26) = m(226800)

since heat gain = heat loss

22.68 × 10^4 = 226800 m2

divide both side by 226800

226800 / 226800 = m2

m2 = 1 kg

5 0
3 years ago
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