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nikitadnepr [17]
3 years ago
10

A hiker walks 20 Km towards the North, then 15 Km Southwards, then 10 Km Eastwards, and finally 12 Km at 30º due East. What is t

he hiker´s displacement?
Physics
1 answer:
Naily [24]3 years ago
5 0

Answer:

Explanation:

We shall represent all displacements in vector form , in terms of i and j . I represents unit displacement towards east and j represents unit displacement in north direction .

First displacement D₁ = 20 j

second displacement D₂ = -15 j

Third displacement D₃ = 10 i

Fourth displacement D₄ = 12 cos30 i + 12 sin30 j  [ 12 cos 30 is displacement towards east and 12 sin30 is displacement towards north ]

Total displacement = 20 j - 15 j + 10 i + 12 cos30 i + 12 sin30 j

= 5 j + 10 i + 10.4 i + 6 j

= 20.4 i + 11 j

Magnitude of displacement = √ ( 20.4² + 11² )

= √ ( 416.16 + 121)

= √ 537.16

= 23.17 m

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An object moving north with an initial velocity of 14m/s accelerates 5m/s squared. What is the final velocity of the object?
OLEGan [10]
The final velocity of the object is 16m\s.
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6 0
3 years ago
The Moon orbits the Earth in an approximately circular path. The position of the moon as a function of time is given by: x(t) =
Aleks [24]

Answer: Average Velocity = - 643.42 i + 512.66 j m/s

Magnitude = 822.7 m/s

Direction = 141.45°

Explanation:

r = 3.84 x 10^8 m

w = 2.46 x 10^-6 rad/s

Formula for Average velocity = displacement / time

at t = 0

x(0) = r

y(0) = 0

at t = 8.45 days

= 8.45 x 24 x 3600 s =730080 sec

w t = 2.46 x 10^-6 x 730080 = 1.80 rad Or 102.90°

xf = r cos(w t) = - 0.2233r

yf = r sin(w t) = 0.9747r

Displacement = (xf - x0)i + (yf - y0)j = -1.2233r i + 0.9747r j

<v> = dispalcement / t = (-1.2233r i + 0.9747r j ) / (730080 s )

= - 643.42 i + 512.66 j m/s

Magnitude

= sqrt(643.42^2 + 512.66^2)

= 822.7 m/s

Direction

= 180 - tan^-1(512.66 / 643.42)

= 141.45°

8 0
3 years ago
Read 2 more answers
Two rams run toward each other. One ram has a mass of 49 kg and runs west
olga nikolaevna [1]

Answer: (d)

Explanation:

Given

Mass of the first ram m_1=49\ kg

The velocity of this ram is v_1=-7\ m/s

Mass of the second ram m_2=52\ kg

The velocity of this ram v_2=9\ m/s

They combined after the collision

Conserving the momentum

\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]

Momentum after the collision will be

\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}

Therefore, option (d) is correct

4 0
3 years ago
If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the
PolarNik [594]

Answer:

a. v₁ = 16.2 m/s

b. μ = 0.251

Explanation:

Given:

θ = 15 ° , r = 100 m , v₂ = 15.0 km / h

a.

To determine v₁ to take a 100 m radius curve banked at 15 °

tan θ  = v₁² / r * g

v₁ = √ r * g * tan θ

v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s

b.

To determine μ friction needed for a frightened

v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg

v₂ = 4.2 m/s

fk = μ * m * g

a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²

a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²

F₁ = m * a₁  ,  F₂ = m * a₂

fk = F₁ - F₂   ⇒  μ * m * g = m * ( a₁ - a₂)

μ * g = a₁ - a₂   ⇒  μ = a₁ - a₂ / g

μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)

μ = 0.251

3 0
4 years ago
Two nuclear reactors provide 3200 MW of power.If the transmission system loses 5.1% of the energy produced,how much power from t
Annette [7]

The power that the customers receive is 163.2 MW

Explanation:

The efficiency of a system is given by

\eta = \frac{P_{out}}{P_{in}}

where

P_{out} is the power in output

P_{in} is the power in input

For the nuclear reactors in this problem, we have:

P_{in} = 3200 MW (power generated by the reactors)

\eta=0.051 (efficiency is 5.1%)

Therefore, the power that reaches the customers is:

P_{out} = \eta P_{in} = (0.051)(3200)=163.2 MW

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

6 0
3 years ago
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