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3 years ago

How would a rise in business investment affect the aggregate demand curve?

Business

2 answers:

vlabodo [156]3 years ago

7 0

The aggregate demand curve shifts to the right

Sever21 [200]3 years ago

6 0

Answer:

Increase in the country's cash supply brings down financing costs, hence diminishes the expense of working together in the business.

When we get the good return during the investment, then the venture spending increments thus also aggregates supply. As total stockpile expands, total interest increments thus costs go up.

Therefore genuine GDP and APL increment. When the business investment get rises then it affected the aggregate curve of demand as it also increase or rise the aggregate supply and also the capacity of the productivity. Then, the investment increase the economical growth.

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A loan commitment of $4.43 million with an up-front fee of 60 basis points and a back-end fee of 35 basis points. The take-down

valentinak56 [21]

Answer:

Total fees paid = $2,700,085

Explanation:

Given:

Loan Amount = $4,430,000

Up-Front basis fee = 60 points

Back-end fee = 35 points

Take down = 40 %

Computation:

Up-Front basis fee = $4,430,000 x 0.0060

Up-Front basis fee = $26,580

Back-end fee = $4,430,000 x 0.0035

Back-end fee = $15,505

Take down amount = $4,430,000 x 40%

Take down amount = $1,772,000

Total fees paid = [$4,430,000 - $1,772,000] + $26,580 + $15,505

Total fees paid = $2,700,085

4 0

3 years ago

A difference between financial accounting income and taxable income that never reverses is called a(n)_____difference. (enter on

soldi70 [24.7K]

Permanent difference

7 0

1 year ago

The cash provided (used) by investing and financing activities is best described as _____. cash provided by investing activities

mojhsa [17]

Answer:

the answer would be 76

Explanation:

3 0

3 years ago

Consider a family that has one working parent, a stay‐at‐home parent, and three children. Two of the children are in elementary

zheka24 [161]

1. The family's total assets = $148,700.

2. The family's total liabilities = $155,500.

3. The family's net worth is ($6,800), which is $148,700 - $155,500.

<h3>What is the family's net worth?</h3>

The family's net worth is the excess of its total assets minus its total liabilities.

The net worth can be <u>positiv</u>e or <u>negative</u>. It is <u>negativ</u>e when the total liabilities exceed the total assets.

<h3>Data and Calculations:</h3>

Assets Liabilities

House on mortgage $89,000 $80,000

Car on auto loan 15,000 15,000

Minivan on auto loan 20,000 16,000

Furnishings 5,000 4,500

Retirement account 15,000

Emergency savings 1,500

Savings 1,000

Checking account 500

CD 1,500

Cash 200

Credit cards 15,000

School loan 25,000

Total $148,700 $155,500

4. Thus, the expenses that would not fall on the balance sheet are:

Payment for school loans of $500 per month
Pre-Kindergarten tuition of $350 per month
Payment for soccer teams of $100 per month.

Learn more about computing net worth at brainly.com/question/12371230

#SPJ1

3 0

3 years ago

The average daily volume of a computer stock in 2011 was muμequals=35.135.1 million shares, according to a reliable source. a s

Jlenok [28]

Required

a. State the hypotheses for the test

b.Construct a 95% confidence interval about the sample mean volume of stocks traded in 2014.

c. Will the researcher reject the null?

<u>Answer</u>

a. Null Hypothesis: μ = 35.1 million

Alternate Hypothesis : μ ≠ 35.1 million

b. CI = 3.708069909 ≤ μ ≤ 53.53193009

c. The critical t value for a two-tailed test at 30 df is ± 2.02. Since the calculated t value at t = -3.315291095 is less than the critical t value, the researcher will reject the null.

b. Since the population standard deviation in unknown, we can construct the confidence interval using t-tables instead of critical Z values.

The formula is:

CI = X̅ ± t₃₉ × (S/√n)

In the term t₃₉, t refers to Student's t table and 39 represents n-1 degrees of freedom (d.f). Since n =40, d.f = 40-1 =39

CI = 28.62 ± 12.7062 × (12.4/√40)

CI = 28.62 ± 24.91193009

CI = 3.708069909 - 53.53193009

c. The test statistic for the test is

t = (X-μ)/ (S/√n)

t = 28.6-35.1/(12.4/√40)

t = -3.315291095

The critical t value for a two-tailed test at 30 df is ± 2.02.

4 0

3 years ago