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Temka [501]
3 years ago
6

Can any one help me with this problem ​

Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0
A - 2
B - 4
C - 3
D - 1
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Find the area of a triangle whose vertices have the coordinates (-1,1) (-1,5) (4,1)
Alekssandra [29.7K]

The triangle that forms is a right-angled triangle. To work out the area, you just do the base × height, all divided by 2.

Therefore, you do 5 (the base) × 4 (the height) and you get 20.

Then you divide by 2 to finish the equation and you should find that the total area of the triangle is 10 units² (20 ÷ 2 = 10).

Hope that helps :)

7 0
3 years ago
Please help me please help please
Galina-37 [17]
\bold{ANSWER:}
b = -12

\bold{SOLUTION:}

4 0
2 years ago
Which sequence of transformations will produce similar but not congruent figures?
RoseWind [281]
A dilation would produce<span> a </span>similar figure. Therefore, the sequence of transformations that will produce a similar but not congruent figures would be the first and the third option. Figure TUVWX is dilated by a scale factor of 6 and then rotated 90° counterclockwise around the origin; and f<span>igure TUVWX is reflected across the x-axis and dilated by a scale factor of 7. Hope this answers your question.</span>
3 0
3 years ago
Solve for x in the equation 2x^2-4x-9=29
Andrews [41]

Answer:

x = 1  ±2sqrt(5)

Step-by-step explanation:

2x^2-4x-9=29

Add 9 to each each side

2x^2-4x-9+9=29+9

2x^2-4x=38

Divide by 2

2/2x^2-4/2x=38/8

x^2 -2x =19

Complete the square

x^2 -2x + (-2/2)^2 = 19 +(-2/2)^2

x^2 -2x +1 = 19+1

(x-1)^1=2 = 20

Take the square root of each side

sqrt((x-1)^2) = ±sqrt(20)

x-1 =  ±sqrt(20)

Add 1 to each side

x-1+1 = 1  ±sqrt(20)

x = 1 ±sqrt(20)

Simplifying the square root of 20

x = 1  ±sqrt(4)sqrt(5)

x = 1  ±2sqrt(5)

3 0
4 years ago
-6(y+15)=-3y+6<br> what value of y makes the equation true
AlladinOne [14]

Answer:

y = -32

Step-by-step explanation:

-6(y+15)=-3y+6

Distribute

-6y - 90 = -3y +6

Add 6y to each side

-6y -90+6y = -3y+6y +6

-90 = 3y+6

Subtract 6 from each side

-90 -6 = 3y +6-6

-96 = 3y

Divide by 3

-96/3 = 3y/3

-32 = y

7 0
3 years ago
Read 2 more answers
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