Answer: All data will be sent in 89.39 hours
Step-by-step explanation:
Data transfer rate: 100 Mbps=100
×
×
=0.3433 
The pigeon can fly 1000 km/day and it needs to fly 400 km (round trip).
Pigeon rate:
=41.67 
Time of round trip: 400 km÷
=9.6 h
So the pigeon can send 1 Tb every 9.6 hours.
If we sum the rates we can get the time for sending all the data:
40 Tb= (0.3433 Tb/h + 1 Tb/9.6h)×t
T= 89.39 hours
The Karger's algorithm relates to graph theory where G=(V,E) is an undirected graph with |E| edges and |V| vertices. The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs. The algorithm is randomized and will, in some cases, give the minimum number of cuts. The more number of trials, the higher probability that the minimum number of cuts will be obtained.
The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.
The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2), which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.
This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.
We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.
Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n
We will use a tool derived from calculus that
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e for x finite.
Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e
Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]
P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n)
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n
Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n) [note: log(n) is natural log]
3x3=9
9+5=14 hope this helps u
<span><span>A.
</span>y= 4 / x</span>
Proportionality or variation is state of relationship or
correlation between two variables It has two types: direct variation or
proportion which states both variables are positively correlation. It is when
both the variables increase or decrease together. On the contrary, indirect
variation or proportion indicates negative relationship or correlation. Elaborately,
the opposite of what happens to direct variation. One increases with the other
variables, you got it, decreases. This correlations are important to consider
because you can determine and identify how two variables relates with one
another.
Notice x = y (direct), y=1/x (indirect)
Answer=7/8
7x3=21
12x2=24
21/24=7/8