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Alinara [238K]
3 years ago
10

five pencils and four pens cost $6.15. three similar pencils and eight owns cost $9.85. how much would you expect to pay for a s

et of eight pencils and seven pens?
Mathematics
1 answer:
stepladder [879]3 years ago
8 0
Here you have to add and subtract
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What is the LCM of 72 and 75​
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3 years ago
Use the formula L= 10 log 10 R, where Is the loudness of a sound and R is the sound's relative intensity. to find out how much l
WINSTONCH [101]

Answer:

X=24.1decibels

Step-by-step explanation:

From the question we are told that:

Loudness function L= 10 log_{10} R

Sound of a person S_p=80\ decibels\ or 10^8

Number of persons talking n=20 people

 

Generally the Relative intensity for 20 people is mathematically given by

Relative intensity forR_{20}=20*10^8

Relative intensity forR_{20}=20^8

Generally the loudness for 20 people is mathematically given by

L_{20}= 10 log_{10} R

L_{20}= 10 log_{10} 20^8

L_{20}= 10 (8 log_{10} 20)

L_{20}= 104.1 decibels

Therefore increase in loudness X is given as

X=104.1-80=-52.90

X=24.1decibels

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2 years ago
How do you do fraction
MakcuM [25]

Answer:

Step-by-step explanation:

7 0
3 years ago
The length of a rectangle is the width minus 8 units. The area of the rectangle is 9 units. What is the length, in units, of the
frez [133]

Length of rectangle is 1 unit  

<u>Solution: </u>

Given that  

Length of a rectangle is width minus 8 units.

Area of rectangle = 9 square units

Need to calculate the length of rectangle.

Let us assume width of rectangle = x

As Length is width minus 8,  

Length of the rectangle = x – 8

\text{ Area of rectangle }=\text{ width of rectangle }\times \text{ Length of the rectangle }

\text{ Area of rectangle }= x\times (x-8)

\text { Area of rectangle }=\left(x^{2}-8 x\right)

As given that area of rectangle = 9 square units

\begin{array}{l}{\Rightarrow x^{2}-8 x=9} \\\\ {\Rightarrow x^{2}-8 x-9=0}\end{array}

On solving above quadratic equation for x, we get

\begin{array}{l}{\Rightarrow x^{2}-9 x+x-9=0} \\\\ {\Rightarrow x(x-9)+1(x-9)=0} \\\\ {\Rightarrow (x-9)(x+1)=0}\end{array}

When x-9 =9, x = 9

When x + 1 = 0, x = -1

As width cannot be negative, so considering x = 9  

\text{ Length of rectangle }= x-8 = 9-8 = 1 \text{ unit }

Hence, Length of rectangle is 1 unit.

5 0
3 years ago
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