Answer:
I cannot answer see no red triangle to Base an answer on sorry is this calculus never took that course
<em>Hi there!</em>
<em>This should be easy,lol!</em>
<em>Answer:</em>
<em />![\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-128%7D%20%3D%20%5Cboxed%7B-128%20%5Csqrt%7B3%7D%20%7D)
<em> (Decimal: -221.702503)</em>
<em />![\sqrt[3]{162} = \boxed{162 \sqrt{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162%7D%20%3D%20%5Cboxed%7B162%20%5Csqrt%7B3%7D%20%7D)
<em> (Decimal: 280.592231)</em>
<em />![\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1000x%5E4%7D%20%3D%20%5Cboxed%7B-1732.050808x%5E4%7D)
<em />
<em>Sorry bout the explanation thingy. Their really long -.-!</em>
<em>But the last one is short so i'll put it for you!</em>
<em>Step-by-step explanation:</em>
<em>∴!For the last one!∴</em>
<em />![\sqrt[3]{-1000x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1000x%5E4%7D)
<em />
<em>Simplifies to:</em>
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<em> </em>
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<em>Have a great day/night!</em>
Answer:
89.99
Step-by-step explanation:
u add i48934yr84 r84
Area of a circle is πr^2.
The radius of the smaller circle with diameter 10 cm is 5 cm.
The radius of the larger circle with diameter 20 cm.is 10 cm.
Area of larger circle : Area of smaller circle
Area of larger circle = 100π.
Area of smaller circle = 25π.
Ratio = 100π : 25π or 100π/25π.
Answer:
5unit
Step-by-step explanation: since area of rectangle = length*width
Here length is (x+2) and width is(2x+3)
(x+2)(2x+3)=91
On further solving
2x^2+75x-85=0
2x^2-10x+17x-85=0
2x(x-5)+17(x-5)=0
(2x+17)(x-5)=0
x=5unit
