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Elza [17]
3 years ago
10

Why does it pi appear in measurement formulas involving circles?​

Mathematics
1 answer:
diamong [38]3 years ago
8 0

Answer:

because it is the ratio or the quotient of the circumference

Step-by-step explanation:

C (the distance around a circle) to the diameter d (the distance across a circle through the center of the circle)

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A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18 \pi18π18, pi
Whitepunk [10]

Answer:

A=81\pi $ m^2

Step-by-step explanation:

Circumference of the column =18\pi $ meters

Circumference of a circle=2\pi r

Therefore:

2\pi r =18\pi $ meters\\2r=18\\r=18 \div 2\\$Radius, r=9 meters

Area of a Circle =\pi r^2

Since radius of the cross section of the column =9 meters

Area of the cross section of the column

=\pi *9^2\\=81\pi $ m^2

5 0
3 years ago
Find the difference: <br> -10 - (-6) = <br><br> A. -4<br><br> B. -16<br><br> C. +4<br><br> D. +16
Tatiana [17]

Answer:

-10-(-6) = -10+6 = -4; A

Step-by-step explanation:


3 0
2 years ago
A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen
Darina [25.2K]

Answer:

100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving y=x^2 about y axis in the interval 0\leq x\leq 3.

Density of the fluid in the tank, D=100\ lbs/ft^3

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, y(0)=0^2=0

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in x=3 in the parabolic equation . This gives,

H=3^2=9\ ft

So, the height of top of tank is, y(3)=H=9\ ft

Now, 5 ft above 'H' means H+5=9+5=14

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

\Delta y=(14-y) ft

Now, area of cross section of the tank is given as:

A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, y=x^2

So, x=\sqrt y

Therefore, radius, r=\sqrt y

Now, area of cross section is, A(y)=\pi (\sqrt y)^2

Work done in pumping the contents to 5 feet above is given as:

W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy

Plug in all the values. This gives,

W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}

7 0
3 years ago
Uh not sure if i put it in the right subject but... help Imao
kondaur [170]

Answer:

yes u did put in right subject

4 0
3 years ago
What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = −16? 1 −0.25 −1 0.25
VLD [36.1K]

The n-th term is given by

a_n=a_1\cdot r^{(n-1)}\qquad\text{where r is the common ratio}

Then we can find the common ratio from the given terms.

\dfrac{a_4}{a_1}=\dfrac{a_1\cdot r^{(4-1)}}{a_1}=r^3=\dfrac{-16}{1024}=\left(\dfrac{-1}{4}\right)^3\\\\r=\dfrac{-1}{4}\\\\a_6=1024\left(\dfrac{-1}{4}\right)^5=-1

The appropriate choice is -1.

8 0
3 years ago
Read 2 more answers
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