Answer:
False, 5 is not a factor of 54.
Answer:

Step-by-step explanation:
Area is the width (6/7 yd) multiplied by the height (1 yd).
6/7 x 1 = 6/7 
You are asking for the condition needed for the
<span>two segments to be perpendicular to each other. </span>
<span>If the slope of one segment is m, then the slope of a perpendicular segment would be -1/m </span>
<span>this means that m2 = -1/m and so m2 x m = -1 </span>
<span>If you look carefully at your choices, the 3rd answer involves the two slope and has the -1. It's </span>
<span>the correct answer.</span>
Answer:
The maximum distance is 17.5 miles
No she can't make to the airport.
Step-by-step explanation:
Given the cab charges $0.8 per mile and $2 for tolls.
let the miles travelled by melissa be x.
The total charge is $
Now given that she can spend a maximum of $16
so the inequality is




Therefore the maximum distance she can travel is 17.5 miles
Since the distance to airport is 25 miles which is greater than 17.5 miles she cannot afford the cab.
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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