Japanese 22 pirate for every two pirate ships he manages

(20) points and brianliest) Write the equation of a line which contains the point (4,3) and (2,5). Remember you must first find

lions [1.4K]

Slope formula
y2-y1/x2-x1
5-3/2-4
2/-2
-1 = slope

y=-1x+b
5=-1(2)+b
5=-2+b
b=7

Your answer:
y= -1x + 7

3 0

2 years ago

Wilton collected $8.50 in dimes and quarters while cleaning his father's truck. If the number of quarters is 3 times the number

dusya [7]

Answer:

Wilton found 10 dimes while cleaning his father's truck.

Step-by-step explanation:

Given that:

Total amount collected = $8.50 = 8.50*100 = 850 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement,

10x+25y=850 Eqn 1

y = 3x Eqn 2

Putting y=3x in Eqn 1

$10x+25(3x)=850\\10x+75x=850\\85x=850$

Dividing both sides by 85

$\frac{85x}{85}=\frac{850}{85}\\x=10$

As x represents dimes, therefore, number of dimes is 10.

Hence,

Wilton found 10 dimes while cleaning his father's truck.

8 0

3 years ago

Which of the following is true of the discriminant for the graph below?

Sonbull [250]

Answer:

Option C. It is zero

Step-by-step explanation:

The graph represents a quadratic equation

The quadratic equation has the form ⇒a x² + b x + c

The discriminant of the quadratic equation is D = b² - 4ac

From the discriminant of the quadratic equation, we can know the type of roots of the quadratic equation.

If D > 0 ⇒ Two real roots.
If D = 0 ⇒ one real roots
If D < 0 ⇒ Two imaginary roots.

The roots of the quadratic equation are the x-intercepts of the function.

As shown at the figure, the quadratic equation has only one point of intersection with the x-axis

So, the function has only one root ⇒ D = 0

So, the discriminant of the quadratic equation = 0

The answer is option C. It is zero

7 0

2 years ago

Please help with this

9966 [12]

Answer:

D

Step-by-step explanation:

The first graph curves down

The second graph is not symmetrical on the y axis

The third graph is much higher than the picture

6 0

2 years ago

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the

Svetlanka [38]

Answer:

The hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be $x.$

And the hotel charge in second city before tax be $y.$

So, as the hotel charge of the second city was 1500 higher than the first.

Thus,

$y=x-1500$ ........(1)

And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.

6% of $x$ + 10% of $y$ = $670.

$\frac{6x}{100} +\frac{10y}{100} =670$

$0.06x+0.10y=670$

Substituting the value of $y$ from equation (1) we get:

$0.06x+0.10(x-1500)=670$

$0.06x+0.10x-150=670$

$0.16x-150=670$

Adding both sides by 150 we get:

$0.16x=820$

Dividing both sides by 0.16 we get:

$x=5125.$

The hotel charge in first city before tax = $5125.

Now, substituting the value of $x$ in equation (1) we get:

$y=x-1500$

$y=5125-1500$

$y=3625.$

The hotel charge in second city before tax = $3625.

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0

3 years ago