Question

Find the point-slope equation for the line that passes through the points (-8,-32) and (3,1). Use the first point in your equation.

Answer 1

Answer:    y+32=3(x+8)

Step-by-step explanation:

First  you need to find the slope.The slope is the change in y divided by the change in x values.

-32 - 1 = -33

-8 - 3 =    -11  

-33/-11 = 3   the slope is 3  

and in point-slope form is  like y-b= m(x-a) where b is a y coordinate and a is the x coordinate.

it could be like   y-1=3(x-3) or y+32= 3(x+8)

Answer 2

Hey there! :)

Answer:

y + 32 = 3(x + 8)

Step-by-step explanation:

Begin by finding the slope of the line using the slope formula:

$m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}$

Plug in the coordinates of the points into the equation:

$m = \frac{1 - (-32)}{3 - (-8)}$

Simplify:

$m = \frac{33}{11}$

m = 3.

Point-slope form is:

y-y₁=m(x-x₁)

Plug in the coordinates of the first point, as well as the slope:

y - (-32) = 3(x - (-8)

y + 32 = 3(x + 8)