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3 years ago

Please can someone help ill give the person who answers brainliest :>

Mathematics

1 answer:

Maru [420]3 years ago

5 0

Answer:

Q: i | P: ii | R: iii

Step-by-step explanation:

And I am gonna write a comment for you, if you just take my answer and get this right it means you have not understood the basics of graphing, and if you do not understand the simplest things you will struggle much more as you further your education.

<u>Keep studying and striving to become better educated!</u>

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Which choice is equivalent to the expression √20 + √80

salantis [7]

Answer:

13.41

Step-by-step explanation:

Hope it helps!

7 0

3 years ago

Read 2 more answers

7÷9932 i need help with this and i have to show the work

Rashid [163]

Answer:

the answer is 7 over 9932!

Step-by-step explanation:

6 0

2 years ago

If two lines are perpendicular, which statement must be true?

Kryger [21]

Answer:

Their slopes are opposites

8 0

2 years ago

A person invest $10,000 into a bank the bank pays 4.75% interest compounded semi annually. To the nearest 10th of a year, how lo

Mama L [17]

Answer:

T is 13.9 years to the nearest 10th of a year

Step-by-step explanation:

In this question, we are to calculate the number of years at which someone who invests a particular amount will have a particular amount based on compound interest.

To calculate the number of years, what we do is to use the compound interest formula.

Mathematically,

A = P(1+ r/n) ^nt

Where A is the final amount after compounding all interests which is $19,200 according to the question

P is the initial amount invested which is $10,000 according to the question

r is the rate which is 4.75% according to the question = 4.75/100 = 0.0475

n is the number of times per year in which interest is compounded. This is 2 as interest is compounded semi-annually

t= ?

we plug these values;

19200 = 10,000(1+0.0475/2)^2t

divide through by 10,000

1.92 = (1+0.02375)^2t

1.92 = (1.02375)^2t

We find the log of both sides

log 1.92 = log [(1.02375)^2t)

log 1.92 = 2tlog 1.02375

2t = log 1.92/log 1.02375

2t = 27.79

t = 27.79/2

t = 13.89 years

The question asks to give answer to the nearest tenth of a year and thus t = 13.9 years

7 0

3 years ago

A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden

solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99% = 1 - 0.99

α = 0.01

and $\frac{\alpha}{2}$ = $\frac{0.01}{2}$

$\frac{\alpha}{2}$ = 0.005

so Z is here

$Z_(\frac{\alpha}{2})$ = 2.576

sample size will be

Sample size n = $(\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)$

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0

3 years ago