A. albatross - blue jay = 3 1/2 - 39/100
================== (3*2)+1/2 - 39/100
================== 7/2 - 39/100
================== 311/100
================== 3.11
b. Golden eagle - seagull = 2 1/4 - 11/5
======================= (2*4)+1/4 - 11/5
======================= 9/4 - 11/5
======================= 1/20
======================= 0.05
You have to do 40 divided by 70 = 175% :)!
<u>We are given:</u>
The function: y = -16t² + 64
where y is the height from ground, t seconds after falling
<u>Part A:</u>
when the droplet would hit the ground, it's height from the ground will be 0
replacing that in the given function:
0 = -16t² + 64
16t² = 64 [adding 16t² on both sides]
t² = 4 [dividing both sides by 16]
t = 2 seconds [taking square root of both sides]
<u>Part B:</u>
for second droplet,
height from ground = 16 feet
time taken = t seconds
acceleration due to gravity = 10 m/s²
initial velocity = 0 m/s
h = ut + (1/2)at² [second equation of motion]
16 = (0)(t) + (1/2)(10)(t²)
16 = 5t²
t² = 16/5
t = 1.8 seconds (approx)
Therefore, the second droplet takes the least amount time to hit the ground
Answer:
Step-by-step explanation:
