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SSSSS [86.1K]
3 years ago
13

Please help me, due today, please dont just guess

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0

Answer: 1 or 2

Step-by-step explanation:

wel3 years ago
3 0

Answer:

10% / .10 is the answer to the question.

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Find the derivative of f(x) = negative 9 divided by x at x = -4. (6 points) 4 divided by 9 16 divided by 9 9 divided by 16 9 div
Len [333]

Answer:

9/16

Step-by-step explanation:

f(x)=-\frac{9}{x}

f(x)=-9x^{-1}

Derivative rule:

f(x)=x^{n} \\

\frac{df}{dx}=nx^{n-1}

Here, n=-1, so

\frac{df}{dx}=(-9)(-1)x^{-2} =\frac{9}{x^{2} }

Evaluating this at x=-4 gives 9/16

5 0
3 years ago
Read 2 more answers
Don’t mind the number 34 but what I need help?
dybincka [34]
U will first need to collect the like terms,
x+16>-5x+4
-5x will go to the other side becoming 5x while 16 while also cross the other side becoming -16
x+5x>4 -16
6x> when 4 is taken out from -16 it becomes - 12
6x>-12 when divided the answer obtained will be -2
3 0
3 years ago
the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of
NeX [460]
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)







8 0
3 years ago
Read 2 more answers
Find the perimeter and area of the figure with the given coordinates:
igor_vitrenko [27]
Sorry but I can’t see the picture
3 0
3 years ago
Write an equation of the parabola that has the same shape as the graph of ​f(x)​, but with the point ​(​,​) as the vertex.
erik [133]

Answer:

y=3(x-9)^2+4

Step-by-step explanation:

To move a parabola horizontally to the right, subtract 9.

To move it upward 4 units, you simply have to add 4.

These do not change the characteristics of the shape. I suggest looking at a set of rules that affect how the parabola moves horizontally and vertically.

5 0
3 years ago
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