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aleksandr82 [10.1K]
2 years ago
6

Ron earns a 15% commission on his sales in addition to a $1500 monthly salary. Determine his monthly sales goal if he budgets $3

750 as his monthly income.
Mathematics
1 answer:
Anastasy [175]2 years ago
5 0

Answer:

His monthly sales goal if he budgets $3750 as his monthly income is $15000.

Step-by-step explanation:

From the information given, the formula to calculate the salary that Ron earns would be:

Total salary=1500+0.15*(monthly sales)

Now, you can replace the total salary and he budgets $3750 as his monthly income and solve for the monthly sales:

3750=1500+0.15*(monthly sales)

3750-1500=0.15*(monthly sales)

monthly sales=2250/0.15

monthly sales=15000

According to this, the answer is that his monthly sales goal if he budgets $3750 as his monthly income is $15000.

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Fill in the box with the appropriate measure.<br> quick please I have only a few min left
Art [367]

Step-by-step explanation:

first box on the left

r=4

d=8

circumference= 2π*4= 8π

area = π*4*4= 16π

Second box on the left

d=6

r= 3

circumference= 2π*3= 6π

area =π*3*3= 9π

third box on the left

A=36π

A=36πarea= π*r*r

A=36πarea= π*r*rr= 6

A=36πarea= π*r*rr= 6d=12

A=36πarea= π*r*rr= 6d=12circumference= 2π*6= 12 π

the last box

C=18π

C=18πC= 2π*r

C=18πC= 2π*rr= 9

C=18πC= 2π*rr= 9d=18

C=18πC= 2π*rr= 9d=18area= π*9*9= 81π

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2 years ago
-13 =\dfrac r9+8−13= <br> 9<br> r<br> ​ <br> +8
inna [77]

Answer:

Ello, estoy aquí para ayudar, pero hablo español, con suerte, entenderás que lo estoy intentando.

56738w7421098548091672949123749279102

Step-by-step explanation:

4 0
3 years ago
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If I have 150,000 crystals, and ONE costume cost 4,000 crystals, how many costumes can I buy total?
MArishka [77]
Okay, think of it this way: 

You have to find how many times 4,000 goes into 150,000. 

This will tell you how many costumes you can buy.

To make this easier, we can divide 4 by 150. (this is proportional to 4,000 and 150,000 since we took 3 zeros from each number; you will get the same answer) 

150/4= 37.5 

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Hope this helped! 
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2 years ago
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

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lora16 [44]

Answer:

108 is your answer.

Step-by-step explanation:

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10 x = 180

x = 180/ 10

x = 18

Then

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I HOPE IT WILL HELP YOU.

Have a great day.

it's me Sopnila.

❤❤❤

8 0
2 years ago
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