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algol [13]
3 years ago
13

Which expression is equivalent to 8a + 20?

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
<h2>Answer: 4(2a + 5)</h2>

i took the test ;)

I hope this helps!

Darina [25.2K]3 years ago
3 0
To determine the expression that is equivalent to 8a + 20, all you have to do is find the common denominator and divide the values by it.

8a + 20
8a/4 + 20/4
4(2a + 5).

The correct solution would cue the second option - 4(2a + 5).
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Determine the area enclosed by y=2x+3, the x-axis and the ordinates x=3 and x=4​
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Answer:

\displaystyle \int\limits^4_3 {2x + 3} \, dx = 10

General Formulas and Concepts:
<u>Calculus</u>

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:                                                           \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                 \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                     \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Property [Addition/Subtraction]:                                                   \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                               \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

y = 2x + 3

<em>x</em>-interval [3, 4]

<em>x</em>-axis

<em>See attachment for graph.</em>

<u>Step 2: Find Area</u>

  1. Substitute in variables [Area of a Region Formula]:                               \displaystyle A = \int\limits^4_3 {2x + 3} \, dx
  2. [Integral] Rewrite [Integration Property - Addition/Subtraction]:           \displaystyle A = \int\limits^4_3 {2x} \, dx + \int\limits^4_3 {3} \, dx
  3. [Integrals] Rewrite [Integration Property - Multiplied Constant]:           \displaystyle A = 2 \int\limits^4_3 {x} \, dx + 3 \int\limits^4_3 {} \, dx
  4. [Integrals] Integrate [Integration Rule - Reverse Power Rule]:               \displaystyle A = 2 \bigg( \frac{x^2}{2} \bigg) \bigg| \limits^4_3 + 3(x) \bigg| \limits^4_3
  5. [Integrals] Integrate [Integration Rule - FTC 1]:                                       \displaystyle A = 2 \bigg( \frac{7}{2} \bigg) + 3(1)
  6. Simplify:                                                                                                     \displaystyle A = 10

∴ the area bounded by the region y = 2x + 3, x-axis, and the coordinates x = 3 and x = 4 is equal to 10.

---

Learn more about integration: brainly.com/question/26401241

Learn more about calculus: brainly.com/question/20197752

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

3 0
2 years ago
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1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
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1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
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2b) The function is only defined for 0 ≤ x < 8. This is its domain.

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y=\left\{ \begin{array}{rcl}x+1 & \mbox{for} & -4\le x \le 1\\-x & \mbox{for} & 1 < x \le 3 \end{array}

6 0
3 years ago
0.909 &gt; 0.91<br>true or false <br>I need an answer and fast​
NeTakaya

Answer:

false

Step-by-step explanation:

0.909 is less than not greater than

3 0
3 years ago
Read 2 more answers
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