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zhuklara [117]
3 years ago
14

A _____ is a type of variable that is not accounted for in a research experiment.

Mathematics
2 answers:
Mariana [72]3 years ago
7 0
Dependent variable or confounding variable, hope this at least got u part of the way there try 2 search it up 
Phantasy [73]3 years ago
6 0
The Answer is C, The independent and the dependent variable are the x and y axis and the only one left is the confounding variable.

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Find the volume of the cylinder
gizmo_the_mogwai [7]

Step-by-step explanation:

volume of cylinder formula pi*r²*h

radius of 9cm is 4.5 as 9/2

so 4.5²*15 is 303.75cm

303.75*pi is 303.75picm³

8 0
3 years ago
The value of the 7 in 27,459 is how many times the value of the 7 in 40,735?
alukav5142 [94]

Answer:

10

Step-by-step explanation:

The 7 in 27,459 is in the <em>thousands</em> place.

The 7 in 40,735 is in the <em>hundreds</em> place.

Any digit in the thousands place has 10 times the value of the same digit in the hundreds place. (The multiplier is 1000, instead of 100.)

_____

In the base-10 number system, each digit location has 10 times the value of the location to its right. The value is determined by the place the digit occupies in the number. That is why it is called a place-value number system.

4 0
3 years ago
Read 2 more answers
I can't even do that tho im not verified
Lelu [443]

h that happens. to me

Step-by-step explanation:

all the time

6 0
3 years ago
Read 2 more answers
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine. How many strawb
Allisa [31]

Since Jasmine has 12 strawberries and George has 6 times has many, you can multiply 12 by 6 to get the number of strawberries George has in his bag.

6 x 12 = 72.

George has 72 strawberries in his bag

8 0
3 years ago
Read 2 more answers
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