9 because 9⁴ gives you that result, you can try on a calculator ;)
Answer:
a= -6
Step-by-step explanation:
Given
a=2+3a+10
In order to find the value of a, we have to isolate a on a single side of the equation
So,
subtracting 3a from both sides
a-3a = 2+10+3a-3a
=>a-3a=12
=> -2a = 12
Dividing both sides by -2
=> -2a/-2 = 12/-2
=> a = -6
The value of a in the given equation is -6 ..
False. Supplementary angles have to add up to 180 degrees, and that is clearly not a flat line lol
Answer:
Step-by-step explanation:
P/6
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.