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Vitek1552 [10]
2 years ago
12

Solve the System by Graphing:

Mathematics
1 answer:
Marat540 [252]2 years ago
7 0

Answer:

  • B) One solution
  • The solution is  (2, -2)
  • The graph is below.

=========================================================

Explanation:

I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.

Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.

--------

To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,

y = (-3/2)x+1

y = (-3/2)*0+1

y = 1

The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.

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Please help me on this
11111nata11111 [884]

Answer: 11 boxes of cards for $72

Step-by-step explanation:

Brennan's equation would be

y=6x+6

Gabriel's Equation would be

y=5x+17

when they spend the same amount the equations will be equal

6x+6=5x+17

x+6= 11

x=11

so 11 boxes they would spend the same

To figure out cost, put 11 into the first equations

y=6(11)+6= 66+6= 72

y=5(11)+17= 55+17 = 72

so they each spent $72

5 0
3 years ago
A quadratic equation is written in four equivalent forms below.
vovangra [49]
Answer: III. y = x^2 - 2x - 48

The y intercept are the points on the graph where the curve hits the y-axis, so it’s the point where x=0
With the equation y=x^2 - 2x - 48 we can easily plug in 0 for x and see that the when x is zero, y is -48.
8 0
3 years ago
The sum of 5 consecutive integers is 110, what is the fourth number in this sequence?
Xelga [282]

The answer is:  " 23 " .

    →  The fourth number in the sequence is:  " 23 " .

_____________________________________

Explanation:

To solve:

 " x + (x + 1) + (x + 2) + (x + 3)  + (x + 4) = 110 " ;

in which:

 "x" = The first number in these sequence;

 "(x + 1 )" = the second number in the sequence;

 "(x + 2)" = the third number in the sequence;

 "(x + 3)" = the fourth number in the sequence;

 "(x + 4)" = the fifth number in the sequence;

_____________________________________

Solve for the "fourth number in the sequence" ; or:  "(x + 3)" ;

_____________________________________

Given:  " x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 110 " ;

                     ↔   " x + x + 1 + x + 2 + x + 3 + x + 4 = 110 " ;

→  Solve for "x" ;  

→  then,  solve for "(x + 3)" ;  

     →  which is the fourth number in this sequence;

_____________________________________

→  " x + x + 1 + x + 2 + x + 3 + x + 4= 110 " ;

      "5x + 1 + 2 + 3 + 4= 110 " ;

      " 5x + 10 =  110 " ;

Solve for "x" :

     Subtract "10" from EACH SIDE of the equation; as follows:

      " 5x + 10 - 10 =  110 - 10 " ;

 to get :

      "  5x = 100 " ;

Now, divide EACH SIDE of the equation by "5" ;

to isolate "x" on one side of the equation; & to solve for "x" ;  as follows:

         5x / 5  = 100 / 5 ;

to get:

         "  x  = 20 "  .

_____________________________________

Now, to find the fourth number in the sequence:

 →  " (x + 3) " ;

→  Substitute "20" for "x" ;

    " x + 3 = 20 + 3 = 23" ;

_____________________________________

The answer is:  " 23 " .

The fourth number in the sequence is:  " 23 " .

_____________________________________

Let us check our work:

If there are five "5" numbers in the sequence, and "23" is the "fourth number" , then:  "24" is the "fifth number" .

As such:  "22" is the "third number" ;  "21" is the "second number" ; and "20" is the "first number" .  Is this consistent with:  "x = 20" as the "first number" ?  Yes!

Thus,  "20 + 21 + 22 + 23 + 25 = ?  110 ?  ? ;

→  20 + 21 = 41 ;

→  41 + 22 = 63 ;

→  63 + 23 = 86 ;

→  86 + 24 = 110 .    Yes!

_____________________________________

Hope this answer is helpful!

Best wishes in your academic pursuits—

 and within the "Brainly" community!

_____________________________________

5 0
3 years ago
Please help with this
tresset_1 [31]

Respuesta:839202829 :VVV

5 0
2 years ago
A recent national survey found that high school students watched an average (mean) of 7.2 movies per month with a population sta
guajiro [1.7K]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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