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3 years ago

Happy birdday. Ur present is 50 pts u frick

Mathematics

2 answers:

In-s [12.5K]3 years ago

7 0

Answer: wait it’s my birthday

Step-by-step explanation: free points for meh :p

scZoUnD [109]3 years ago

7 0

Yuh thanks for da points

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the students on a decorating committee create a banner. The length of the banner is 2.5 times its width. The length of the banne

Lilit [14]

The width is 8 feet

20 divided by 2.5 equals 8 feet

4 0

3 years ago

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Remember that you may need to regroup to subtract. 651,784 - 482,638=

Mazyrski [523]

Answer:

169146

Step-by-step explanation:

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3 years ago

Two of the exterior angles of a triangle are $158^\circ$ and $99^\circ.$ Find the third exterior angle, in degrees.

Lisa [10]

Answer:

The third exterior angle is $103^o$

Step-by-step explanation:

Given

$\theta = 158^o$

$\alpha = 99^o$

Required

The third exterior angle $(\beta)$

The exterior angles of a triangle add up to 360 degrees.

So:

$\theta + \alpha + \beta = 360^o$

Make $\beta$ the subject

$\beta = 360^o - (\theta + \alpha)$

Substitute known values

$\beta = 360^o - (158^o + 99^o)$

$\beta = 103^o$

4 0

3 years ago

Can someone help me please?

ladessa [460]

Answer:

25/28 thats your answer

4 0

3 years ago

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Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago