Answer: Surface area = 68π inches²
Step-by-step explanation:
The formula for determining the total surface area of the circular cylindrical metallic rod is expressed as
Total surface area = 2πr² + 2πrh
Where
r represents the radius of the cylindrical rod.
h represents the height of the cylindrical rod.
π is a constant whose value is 3.14
From the information given,
Radius = 2 inches
Height = 15 inches
Therefore,
Surface area = (2 × π × 2²) + 2 × π × 2 × 15) = 8π + 60π
Surface area = 68π inches²
Answer:
D
Step-by-step explanation:
Because you have to do work
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
AB = 
Step-by-step explanation:
calculate the distance using the distance formula
d = 
with (x₁, y₁ ) = B (3, 2 ) and (x₂, y₂ ) = A (7, 4 )
AB = 
= 
= 
=
≈ 4.47 ( to 2 dec. places )
