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3 years ago

Which ordered pair is a solution of the equation 2x − y = 9?

2 answers:

6 0

You can try by plugging each ordered pair and seeing if the equation comes out true.

(5, 1)

2 * 5 - 1 = 9

That's correct so C is the correct answer.

levacccp [35]3 years ago

4 0

Answer:

5,1

Step-by-step explanation:

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graph the function f (x) = x^2 + 4x -5. on the coordinate plane. (a) What are the x-intercepts? (b) What are the y-intercepts? (

Butoxors [25]

Answer:

a) (-5,0) and (1,0)

b) (0,-5)

c) minimum

See attached graph.

Step-by-step explanation:

To graph the function, find the vertex of the function find (-b/2a, f(-b/2a)). Substitute b = 4 and a = 1.

-4/2(1) = -4/2 = -2

f(-2) = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -4 - 5 = -9

Plot the point (-2,-9). Then two points two points on either side like x = -1 and x = -3. Substitute x = -1 and x = -3

f(-1) = (-1)^2 + 4 (-1) - 5 = 1 - 4 - 5 = -8

Plot the point (-1,-8).

f(-3) = (-3)^2 + 4(-3) - 5 = 9 - 12 - 5 = -8

Plot the point (-3,-8).

See the attached graph.

The features of the graph are:

a) (-5,0) and (1,0)

b) (0,-5)

c) minimum

5 0

3 years ago

If the product of two identical number is one thousand twenty four. Find out of the numbers

GaryK [48]

Answer:

Step-by-step explanation:

1,024 will be a perfect square if it is the product of 2 of the same numbers:

Calculate the square root of 1024:

$\sqrt{1024}$

= 32

So, the number is 32

3 0

2 years ago

Read 2 more answers

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):