This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Answer:
42.68
Step-by-step explanation:
21.34 * 2= 42.68
Answer:
Minimum percent of the vote that candidate Towne is expected to recieve:
m=51% - 6.3% * 51% =47.787%
Maximum percent of the vote that candidate Towne is expected to recieve:
M=51% + 6.3% * 51% = 54.213%
Solution:
Margin of error: E=6.3%
Minimum percent of the vote that candidate Towne is expected to recieve:
m=51% - E * 51%
m=51% - 6.3% * 51%
m=51% - 51% * 6.3 / 100
m=51% - 3.213%
m=47.787%
Maximum percent of the vote that candidate Towne is expected to recieve:
M=51% + E * 51%
M=51% + 6.3% * 51%
M=51% + 51% * 6.3 / 100
M=51% + 3.213%
M=54.213%
The area of a circle is given by
We can solve this equation for r: divide both sides by pi:
Consider the (positive) square root of both sides:
So, in your case, we have
First, subtract 7 on both sides. Now, you have 4x<1. Divide by 4 on both sides. Finally, you get x<1/4 (a quarter or said as one-fourth). So, x<1/4.
