Answer:
Increasing on the interval(s) ![-2\leq x\leq -4](https://tex.z-dn.net/?f=-2%5Cleq%20x%5Cleq%20-4)
Decreasing on the interval(s) ![-1\leq y\leq 1](https://tex.z-dn.net/?f=-1%5Cleq%20y%5Cleq%201)
Step-by-step explanation:
Anytime the graph is going upward, the function is increasing. However, anytime the graph goes down, the function is decreasing. Look at the image below for further reference. Also, when the function is increasing, the slope is positive, and when the function is decreasing the slope is negative.
The increasing interval of the graph is -3
The decreasing interval of the graph is 0.5
Since the values are in the middle of the interval, it automatically becomes the answer.
So you would start with the square and do 18 times 18 which equals 324 then for the triangle it's base times height divided by two so 9 times 18 divided by 2 which equals 81 then you add the triangle plus the square and your final answer is
answer:405
Answer:
One variable equation that is (4800/x) represents percentage of Emily's dinner fat intake compared to total daily allowance of x gram.
Step-by-step explanation:
lets assume the variable for total daily allowance
lets say total daily allowance of fat = x grams
Fat consumed at dinner = 48 grams
Fat consumed at dinner in percentage = (Fat consumed at dinner/total daily allowance of fat) × 100
= (48 grams/x grams)×100=(4800/x)%
so (4800/x)%
So one variable equation that is (4800/x) represents percentage of Emily's dinner fat intake compared to total daily allowance of x gram.
lets take one example
lets says total daily allowance of fat for Emily = 100gm
so from derived equation that is 4800/x , we can get required percentage by putting x = total daily allowance of fat = 100gm
=4800/100 = 48%.
you can change value of variable x according to total daily allowance and get the required dinner intake percentage by equation 4800/x.