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Anna71 [15]
2 years ago
9

A new Community Center is being built in Oak Valley. The perimeter of the rectangular playing field is 382 yards. The length of

the field is 9 yards less than triple the width. What are the dimensions of the playing​ field?
Mathematics
1 answer:
vesna_86 [32]2 years ago
3 0

Answer:

The width is 50 yards and the length is 141 yards.

Step-by-step explanation:

Let's call: L the length of the field and W the width of the field.

From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:

2L + 2W = 382

Because the perimeter of a rectangle is the sum of two times the length with two times the width.

Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:

L = 3W - 9

So, replacing this last equation on the first one and solving for W, we get:

2L + 2W = 382

2(3W - 9) + 2W = 382

6W -18 +2W = 382

8W - 18 = 382

8W = 382 + 18

8W = 400

W = 400/8

W = 50

Replacing W by 50 on the following equation, we get:

L = 3W - 9

L = 3(50) - 9

L = 141

So, the width of the rectangular field is 50 yards and the length is 141 yards.

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4 0
3 years ago
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Step-by-step explanation:

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Eya is 5 years younger than 3 times Bills age. If Eya is 28 how old is Bill?
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hope this helps
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3 years ago
Suppose ΔXYZ is given, and you want to construct ΔABC so that the triangles are congruent. Which constructions would guarantee t
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Answer:

A: constructing ΔABC so that AB ≅ XY, BC ≅ YZ, and CA ≅ ZX

C: constructing ΔABC so that AB ≅ XY, CA ≅ ZX, and ∠A ≅ ∠X

Step-by-step explanation:

* Lets revise the ways of constructing a triangle

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# You must have length of one side and measures of two angles which

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