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xxMikexx [17]
2 years ago
7

Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.

Mathematics
2 answers:
dusya [7]2 years ago
5 0

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

Leona [35]2 years ago
5 0

Answer:

k>1 1/3

Step-by-step explanation:

i have rsm too bro

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Dose the perimeter of a square vary directly with the side length?
tankabanditka [31]

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3 years ago
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Y=8-2x when x=8 the value of y
Lera25 [3.4K]

Answer:

-8

Step-by-step explanation:

Given that x and y are two variables.  they are related by the function

y =8-2x

Since x and y are related, given one value we can find the other using this equation.

In our question, given that x =8

Substitute x value in the equation

y = 8-2x

y =8-2(8) = -8

Hence answer is -8:


Verify:  We verify by putting -8 for y and check whether x =8

-8=8-2x

Or 2x = 16

x =8

Verified

8 0
3 years ago
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X=-2y+16<br> 4x+8y=32<br> substitutional equation
Dahasolnce [82]
4(-2y + 16) + 8y = 32
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Answer: no solution
5 0
3 years ago
Solve x2 - 8x = 20 by completing the square. Which is the solution set of the equation?
Artyom0805 [142]

Answer:

{-2,10}

Step-by-step explanation:

x^2 - 8x = 20

Take the coefficient of x

-8

Divide by 2

-8/2 =-4

Square it

(-4)^2 =16

Add this to each side

x^2 - 8x+16 = 20+16

x^2 - 8x+16 = 36

The left hand side becomes( x + (-8/2) )^2

(x - 4)^2 = 36

Take the square root of each side

sqrt((x - 4)^2) =±sqrt( 36)

x-4 = ±6

Add 4 to each side

x-4+4 = 4±6

x = 4±6

x = 4+6       x = 4-6

x = 10        x = -2

3 0
4 years ago
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