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3 years ago

Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.

Mathematics

2 answers:

dusya [7]3 years ago

5 0

The given equation has no solution when K is any real number and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

Leona [35]3 years ago

5 0

Answer:

k>1 1/3

Step-by-step explanation:

i have rsm too bro

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3 years ago

A 9m long ladder rests at 9m below a vertical wall. If the angle of elevation of the top of the wall from the foot of the ladder

Arte-miy333 [17]

Height of the wall is 27 m.

<u>Explanation:</u>

Let the height of the wall = h

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4 years ago

The sum of two numbers is 22 and their difference is 12. what are the two numbers?

Reil [10]

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x = 34

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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