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xxMikexx [17]
2 years ago
7

Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.

Mathematics
2 answers:
dusya [7]2 years ago
5 0

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

Leona [35]2 years ago
5 0

Answer:

k>1 1/3

Step-by-step explanation:

i have rsm too bro

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