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OLga [1]
2 years ago
8

The pie chart below illustrates the future plans of 200members of St.Thomas graduating class.

Mathematics
1 answer:
ruslelena [56]2 years ago
8 0

Answer:

<h2>a) approximately 133 graduates</h2><h2>b) approximately 120°</h2>

Step-by-step explanation:

a) the number of graduates planning to continue studying :

= (37 1/2% + 12 1/2% + 16 2/3%) × 200

=\frac{\left( 37\frac{1}{2} +12\frac{1}{2} +16\frac{2}{3} \right)  }{100} \times200

= (37.5 + 12.5 + 16.666666666667)×2

= 133.333333333334

…………………………………

b) the measurement of the angle representing those who plan to work :

= (360× 33 1/2)÷100

= (360× 33.333333333333)÷100

=119.999999999999

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lukranit [14]

Answer:

449.60 or yellow

Step-by-step explanation:

5 0
3 years ago
Here is a simple probability model for multiple-choice tests. Suppose that each student has probability p of correctly answering
Alla [95]

Answer:

a) The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

Step-by-step explanation:

a) To approximate this distribution we have to calculate the mean and the standard distribution.

The mean is the proportion p=0.85.

The standard deviation can be calculates as:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{100} }=0.04

To calculate the probability that Jodi scores 78% or less on a 100-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.04} =-1.75

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) In this case, the number of questions is 250, so the standard deviation needs to be calculated again:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{250} }=0.02

To calculate the probability that Jodi scores 78% or less on a 250-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.02} =-3.5

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

6 0
3 years ago
A=(1/2)bh Solve the formula for h. Please show the steps of how you got the answer!
Flauer [41]
A = 1/2bh...for h
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5 0
3 years ago
Read 2 more answers
How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?
alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique  10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

nPr=\frac{n!}{(n-r)!}\\

Now, n = 10 [total] and r is 2, so we have:

nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90

So, there can be 90 arrangements

3 0
3 years ago
The following menu items were ordered at a pizza parlor on Friday. 3 salads, 8 pizzas, 4 sides of breadsticks, and 5 pepperoni c
den301095 [7]

Answer:

Using proportions, the pizza parlor should expect 20 breadsticks and 25 calzone orders if there were 100 total orders.

Step-by-step explanation:

Orders:

Salads                           3

Pizzas                           8

Sides of breadsticks   4

Pepperoni calzones    5

Total orders:              20


Proportion of sides breadsticks=4/20=0.2

Proportion of pepperoni calzones=5/20=0.25


For 100 total orders:

Sides of breadsticks=0.2(100)=20

Pepperoni calzones=0.25(100)=25


6 0
3 years ago
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