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2 years ago

HELP!

Mathematics

1 answer:

Katena32 [7]2 years ago

3 0

Answer:
B. Yes, because it touches the y-axis exactly one time
C. Yes, because each x-value has exactly on corresponding y-value

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Anyone know this question?<br><br>Just B please

Gre4nikov [31]

Answer:

52% and 7

Step-by-step explanation:

There are 25 squares of which 13 are shaded , then

$\frac{13}{25}$ × 100% = 13 × 4% = 52°

(b)

1 square represents $\frac{1}{25}$ × 100% = 1 × 4% = 4%

Then 80% = 80% ÷ 4% = 20

That is for 80% , 20 squares require to be shaded

That is 7 more than the 13 already shaded

4 0

2 years ago

Please help with the problem in the picture ^ I’ll give brainliest if you give me a small explanation! :)

kolbaska11 [484]

Answer:

When y=276, x= 23

Step-by-step explanation:

Since they're directly proportional, when divided they have to equal the same.

180/15= 12 and 276/23= 12

4 0

2 years ago

Write the sentence as an inequality.

kramer

Answer:

N < 6 or N $\leq$ -7 or N > 12

Hope this helps. <em>lmk</em>.

6 0

2 years ago

After some snacks at McDonalds at Lower Bonifacio Street, Kristina drove 145 meters towards the three-way junction and turns rig

vaieri [72.5K]

Answer:

125 m

Step-by-step explanation:

The path of Kristina is in the shape of a right triangle where, the perpendicular is the path from the McDonalds to the three-way junction which is 145 m and the shortest distance between the McDonalds and the church is 191.442 m.

By Pythagoras theorem

$145^2+x^2=191.442^2\\\Rightarrow x=\sqrt{191.442^2-145^2}\\\Rightarrow x=125\ \text{m}$

Christina had to travel 125 m from the three-way junction to the church.

5 0

2 years ago

Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I

sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

$speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)$

Back from the store:

$s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)$

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

$\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles$

∴ length of trip to the store = t₁

from eqn (1)

$t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours$

7 0

2 years ago