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2 years ago

What is 55 degrees in radian measure as a multiple of pi

1 answer:

8 0

To change degrees to radian we have to use a rule :

Rad=degree/180/π

Rad = 55/180/π

Final answer:

Rad= (11/36)π [this answer is In pi]

Rad= 0.96 [this answers is the simplified version]

You might be interested in

If the diameter of circle a measures half of the diameter of circle b, then the area of circle b is how many times the area of c

Eduardwww [97]

Circle b:

Diameter = x

Radius = $\frac{x}{2}$

Area = $\pi r^{2} = \pi ( \frac{x}{2} )^{2} = \frac{ \pi x^{2} }{4}$

Circle a:

Diameter = $\frac{x}{2}$

Radius = $\frac{x}{2} * \frac{1}{2} = \frac{x}{4}$

Area = $\pi r^{2} = \pi ( \frac{x}{4} )^{2} = \frac{ \pi x^{2} }{16}$

Thus,

Area of circle b to area of circle a

= $\frac{ \pi x^{2} }{4}$ ÷ $\frac{ \pi x^{2} }{16}$

= $\frac{ \pi x^{2} }{4}$ × $\frac{ 16 }{\pi x^{2}}$

= 4

Hence, the area of circle b is 4 times the area of circle a.

5 0

3 years ago

A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2

dlinn [17]

Answer:

The surface area of the second cylinder is equal to $9.33\ m^{2}$

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

$z^{2}=\frac{x}{y}$

Step 1

Find the scale factor

$z=\frac{2}{6}=\frac{1}{3}$

Step 2

Find the surface area of the second cylinder

we have

$z=\frac{1}{3}$

$y=84\ m^{2}$

substitute and solve for x

$(\frac{1}{3})^{2}=\frac{x}{84}$

$x=\frac{1}{9}*84=9.33\ m^{2}$

5 0

3 years ago

There are 20 students on the schools student council. A special homecoming dance committee is to be formed by randomly selecting

babymother [125]

You have to take 20/7 and you get a answer of <span>2.85 as a decimal. or a mixed number of 2 17/20</span>

3 0

3 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$