3 3%4×2 4%5 anything with a % in between is a fraction

How many 2's must be multiplied for the product to be a number between 100 and 200

Advocard [28]

50. 2x50 = 100. To be safe I would go with any number Between 50 and 100

6 0

3 years ago

Read 2 more answers

Can someone answer this please and please answer it correctly please show work I need it today

Lostsunrise [7]

Answer: 45

Step-by-step explanation:

Total number of 8th graders that signed up = 30

9 dropped out. So the total number 8th graders on board the game

= 30 - 9 = 21

46 2/3 % of the club are 8th graders i.e 21

Let T be the total number of students in the club

46 2/3 % T = 21

(140/3)% T = 21

(140/300)T = 21

T = (21x300)/140 = 45

Therefore, there are 45 students on the club

3 0

3 years ago

Last week Kellie ran 28 miles this week she ran 32 miles what was the percent change in the number of miles she ran

wel

Kelli ran 4 more miles than the week before, so to find what percent that is of 28, divide.

4 / 28 = 0.142857143, or ~14.29%

Kelli ran 14.2857143% or about 14.29% more miles than last week.

8 0

3 years ago

Circumference= 14.4 units Area=

Gemiola [76]

You need to fine the radius by dividing the circumference by 2 and then multiply that by pi (3.14) or (22/7)

6 0

3 years ago

Recall the equation for a circle with center (h, k) and radius r. At what point in the first quadrant does the line with equatio

lina2011 [118]

Answer:

The point of intersection is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

$y=0.5x+5$

Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is (0, 5), h = 0 and k = 5. The radius is 3. So, r = 3. Substitute:

$(x-0)^2+(y-5)^2=(3)^2$

Simplify:

$x^2+(y-5)^2=9$

At the point where the two equations intersect, its x-coordinate and y-coordinate will be the same. Therefore, we can substitute the equation of the line into the equation of the circle and solve for x. So:

$x^2+((0.5x+5)-5)^2=9$

Simplify:

$x^2+(0.5x)^2=9$

Square:

$x^2+0.25x^2=9$

Combine like terms:

$\displaystyle 1.25x^2=\frac{5}{4}x^2=9$

Solve for x:

$\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}$

Note that since we are looking for the point of intersection in QI, x should be positive. So, we can ignore the negative answer.

To find the y-coordinate, substitute the x-value back into either equation. Using the linear equation:

$\displaystyle y=0.5\left(\frac{6\sqrt{5}}{5}\right)+5=\frac{3\sqrt{5}}{5}+5\approx 6.34$

So, the point of intersection in QI is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

6 0

2 years ago