Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you! mark me as brainliest pls
§ALEX§
Answer:
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Step-by-step explanation:
Answer:
Charlie's solution is incorrect.
Part A: The equation must be divided by the number next to the variable. So 5x will be divided by 5 which will equal x, and 30 will be divided by 5 which equals 6. The final answer will be x=6.
Part B: The equation will have one solution because there is only one way to solve it.
A sector is cut out from a circular sheet of paper, and the two edges of the cut are joined together (with no overlap) to form a cone. The cone formed has radius 6 and volume 96 pie . What is the number of degrees in the sector that was cut off?
