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3 years ago

Which of the following expressions is equivalent to the one shown below (3/2)^8

Mathematics

1 answer:

vichka [17]3 years ago

8 0

Option B is the right answer

Step-by-step explanation:

Given expression is:

$(\frac{3}{2})^8$

The exponent properties are used to solve these type of questions,

One of the property states that if an exponent is applied to a fraction, it can be applied to the numerator and denominator separately.

so,

for the given expression, the exponent 8 will be applied to 2 and 3 separately

$(\frac{3}{2})^8 = \frac{3^8}{2^8}$

Hence,

Option B is the right answer

Keywords: Exponents, fractions

Learn more about exponents at:

#LearnwithBrainly

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PLEASE HELP!! It’s due today and i don’t know how to do it.

lara [203]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find S5 for a geometric series for which a1=81 and r=1/9.

Minchanka [31]

ANSWER

$S_5=91\frac{10}{81}$

EXPLANATION

The sum of the first $n$ terms of a geometric sequence is given by;

$S_n=\frac{a_1(1-r^n)}{1-r} ,-1$

Where $n$ , is the number of terms and $a_1$ is the first term.

When $n=5$ , we have $a_1=81$ , we get;

$S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}$

$S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}$

$S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}$

$S_5=\frac{7381}{81}$

$S_5=91\frac{10}{81}$

6 0

3 years ago

(02.03) if granola costs $2.20 per pound, how much does 0.8 pound of granola cost?

Karolina [17]

2.20 per pound

2.20 x 0.80 = 1.76

0.8 pounds cost $1.76

5 0

4 years ago

Read 2 more answers

Pls, help me it has been a missing assignment for too long :/

Natasha2012 [34]

Answer:

Snail A: 0, 5, 10, 15, 20, 25, 30

Snail A travels at a rate of 30 inches in 1 hour or 30 inches per hour.

Snail B: 0, 3, 6, 9, 12, 15, 18

Snail B travels at a rate of 18 inches in 1 hour or 18 inches per hour.

Snail C: 0, 6, 12, 18, 24, 30, 36

Snail C travels at a rate of 36 inches in 1 hour or 36 inches per hour.

Snail D: 0, 4, 8, 12, 16, 20, 24

Snail D travels at a rate of 24 inches in 1 hour or 24 inches per hour.

3 0

3 years ago

Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus

quester [9]

Hi!

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

$t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510$

To calculate the degrees of freedom you need to use the following equation:

$df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89$ ≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.

5 0

4 years ago