3 tens= 30
3 tens 3 tenth= 30.3
30-30.3= -0.3
We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
s = (a + b + c) / 2
Substituting for the base,
s = (12 + 12 + 12)/ 2 = 18
A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
s = (10 + 10 + 12) / 2 = 16
A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
total area = 144 + 62.35 = 206.35
Step-by-step explanation:
please don't understand the question. will be happy if you take a shot of it.
Thanks
Answer:
It's 81
Step-by-step explanation:
2^5 is 2*2*2*2*2 or 32
7^2 is 7*7 or 49
Add them together... 81