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bazaltina [42]
2 years ago
9

Which of the following polynomials has solutions that are not real numbers?

Mathematics
1 answer:
8090 [49]2 years ago
3 0
Assuming this question associates "solutions" with "zeros", then the answer is

   x^2 + 2x + 3 

======

If we set x^2 + 2x + 3 to equal 0, we have

   x^2 + 2x + 3 = 0

The discriminant of this equation of the form ax² + bx + c = 0 is

   discriminant = b² - 4ac = 2^2 - 4(1)(3) = -8

The discriminant is negative, so there are no real solutions (the discriminant is under a square root in the quadratic equation; square root of a negative number is not a real number)
                       
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Kristen can lift 133% of what Jane can lift. How many times more is that?
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The weight Kristen can lift is 1.3 times more than Jane's

<h3>How to determine the number of times?</h3>

The given paramater can be represented using the following equation

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Step-by-step explanation:

After each bounce, the height it reach is 3/4 the previous one.

Let the height of nth bounce be denoted as h_n and the first bounce is h_1.

We are given that h_1 = 60 cm. Following the rule in the problem, we get:

h_2 = (3/4)h_1 = (3/4)60

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