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Butoxors [25]
4 years ago
7

How many significant figures are in this number? 0.00708900

Chemistry
2 answers:
Norma-Jean [14]4 years ago
4 0
Don’t know sorry 1.627
marusya05 [52]4 years ago
3 0
The answer is 6. The two front 0’s after the decimal point are not significant and everything after that is significant which because 1. Non zero numbers are significant
2. Zeros between non zero numbers are significant 3. Trailing zeros are significant (in decimals
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Someone pls help me I will make you brain
Anna35 [415]

Answer:

A catalytic converter

Explanation:

Diesel filters are used to clean fuel not emissions, engine injection puts fuel directly into the engine and a transmission clutch changes the cars transmission.

6 0
3 years ago
Read 2 more answers
A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a
deff fn [24]

Answer:

A) E_{a} = 350KJ/mol, E_{a} = 50KJ/mol, E_{a} = 50KJ/mol

     A = 1.5×10^{-7}s^{-1}, A = 1.9×10^{-7} s^{-1}, A=1.5×10^{-7} s^{-1}

B) 4.469

Explanation:

From Arrhenius equation

      K=Ae^{\frac{E_{a} }{RT} }

where; K = Rate of constant

            A = Pre exponetial factor

            E_{a} = Activation Energy

             R = Universal constant

             T = Temperature in Kelvin

Given parameters:

E_{a} =165KJ/mol

T_{1}=505K

T_{2}=525K

R=8.314JK^{-1}mol^{-1}

taking logarithm on both sides of the equation we have;

InK=InA-\frac{E_{a} }{RT}

since we have the rate of two different temperature the equation can be derived as:

In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )

In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1}  }.(\frac{1}{505} -\frac{1}{525} )

In(\frac{K_{2} }{K_{1} } )= 19846.04×7.544×10^{-5} = 1.497

\frac{K_{2} }{K_{1} } =e^{1.497} = 4.469

 

6 0
3 years ago
Given the following reactions, what is the overall enthalpy change for the following reaction?
Elenna [48]

Answer:

-176.0 kJ/mol

Explanation:

Let's consider the following balanced reaction.

NH₃(g) + HCl(g) → NH₄Cl(s)

We can calculate the standard enthalpy change for the reaction (ΔH°rxn) using the following expression.

ΔH°rxn = 1 mol × ΔH°f(NH₄Cl(s)) - 1 mol × ΔH°f(NH₃(g)) - 1 mol × ΔH°f(HCl(g))

ΔH°rxn = 1 mol × (-314.4 kJ/mol) - 1 mol × (-46.1 kJ/mol) - 1 mol × (-92.3 kJ/mol)

ΔH°rxn = -176.0 kJ/mol

8 0
3 years ago
Elements in the first group of the periodic table are
Anna007 [38]

Answer:alkali metals

Explanation:

6 0
3 years ago
Which energy form is missing from the energy transformation of a flashlight?
Tems11 [23]

Answer: Electrical

Explanation: The chemical energy from the battery converts into electrical energy which powers the bulb converting it into light energy.

8 0
4 years ago
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