Answer :
Explanation : To find density, we can use the formula as given below;
density ρ =
Here, we have the mass as 89.6 g and the volume is ,
on calculating we get,
This means that the density of the copper sample is
2nd option
Heat could transfer from object A to B
The reason : higher kinetic energy means the particles in A are moving /vibrating faster. This is a reason due to hight temperature.
The safety feature aimed at keeping nuclear radiation contained is steel-reinforced concrete.
<h3>What is nuclear power plant?</h3>
A nuclear power plant is a building with reactors that contain controlled nuclear reactions to produce energy.
Nuclear power plants are able to generate warm water by using atomic properties of matter (i.e.,m the process of nuclear fission), which is in turn converted into steam to move turbines.
The walls of nuclear power reactors are composed of steel-reinforced concrete in order to avoid radiation release.
In conclusion, the safety standard property that maintains nuclear radiation contained is steel-reinforced concrete.
Learn more about nuclear power plants here:
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Answer:
Explanation:
N₂ + 3 H₂ → 2 NH₃
1 mole 3 moles 2 moles
3.45 moles 10.35moles 6.90 moles
So 3.45 moles of nitrogen will require 10.35 moles of hydrogen
But hydrogen available is only 4.85 so this gas is the limiting reagent and product will be formed according to its mass .
a )
3 moles of hydrogen can form 2 moles of ammonia
4.85 moles of hydrogen will form 2 x 4.85 / 3 moles of ammonia
= 3.23 moles .
b ) hydrogen is the limiting reagent .
c ) Excess reactant is nitrogen
3 moles hydrogen need 1 mole of nitrogen
4.85 moles of hydrogen will need 4.85 / 3 moles of nitrogen
= 1.62 moles of nitrogen .
excess nitrogen = 3.45 - 1.62
= 1.83 moles.
The volume of O₂ : 21 L
<h3>Further explanation</h3>
Given
8.7 grams of C₂H₄
Required
Volume O₂
Solution
Reaction
C₂H₄ + 3 O₂ ⇒ 2 CO₂ + 2 H₂O
mol C₂H₄(MW= 28 g/mol) :
= mass : MW
= 8.7 g : 28 g/mol
= 0.311
From the equation, mol O₂ :
= 3/1 x mol C₂H₄
= 3/1 x 0.311
= 0.933
At STP, 1 mol gas=22.4 L, so for 0.933 mol :
= 0.933 x 22.4 L
= 20.899 L ≈ 21 L