Help please!!!! I only have a couple mins

If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0° C to 97.0° C, what mass is the sample

LiRa [457]

Data:
Q (Amount of heat) = 832 J
m (mass) = ?
c (Specific heat) = <span>0.90 J/(g × ° C)
T (final) = 97 ºC
To (initial) = 20 ºC
</span>ΔT = T - To → ΔT = 97 - 20 → ΔT = 77 ºC

Formula:
Q = m*c*ΔT

Solving:
Q = m*c*ΔT
832 = m*0.90*77
832 = 69.3m
69.3m = 832
$m = \frac{832}{69.3}$
$\boxed{\boxed{m \approx 12.00\:g}}\end{array}}\qquad\quad\checkmark$

5 0

3 years ago

How did the development of the earliest idea about atoms differ from the later work of scientists?

gtnhenbr [62]

The correct answer is C. It was based on the thoughts of an early philosopher.

Explanation:

An atom is a basic and smallest unit that composes matter and that determine the properties of elements. Regarding the development of ideas related to atoms these did not begin in science but in philosophy; indeed the first person that proposed matter or elements were composed of certain smaller units was the philosophers Leucippus and his pupil Democritus in Ancient Greece, who stated atoms were eternal, infinite and defined the qualities of an object, idea that was supported by other Greek philosophers. But it was not until 16th and 17th centuries after the Middle Ages that the term re-emerged and until the 19th century it was officially proposed and there were experiments by scientists that later became a theory. Therefore, the development of the earliest idea about attoms differs from later work of scientists is that the earliest idea was based on the thoughts of an early philosopher.

4 0

3 years ago

Read 2 more answers

A 25.0 ml sample of water at 90 °c has a mass of 24.12 g. Calculate the density of water at this temperature.

ycow [4]

solution:

Density of water the density of water is greatest at about four degrees C (39.2Â° F or 277degrees Kelvin) which is a density of 1.000 kg per liter (62.4 pounds per cubic foot). Liquids expand slightly as their temperature is raised, but liquid water is denser than solid water (ice). That is why ice floats: it is less dense than liquid water. That is due to the crystal structure of ice. When water freezes, its volume increases about nine percent. 277 K. Density rho = mass m / Volume V. Water has a density of 1,000 kg/m3 = 1,000 g/L = 1.000 kg/dm3 = 1.000 kg/L = 1.000 g/cm3 = 1.000 g/mL at the temperature of 3.98 degrees Celsius. Temperature in degrees Celsius and the density of water: 1

At 4 Â°C, its density is the greatest and is equal to 1000 kilograms per cubic meter (SI unit). At any other temperature, its density is less than 1000 kilograms per cubic meter. The answer "1.0" is wrong. Water is unique in that it is one of the only substances that actually expands and becomes less dense as the temperature increases. Water molecules (H 2 O) have a special shape and arrangement; this is why ice floats above the warmer water on a frozen lake. To convert grams/cm3 or grams/mL (1 cm 3 = 1 mL) into other units, use these conversions: 1 dry ounce = 28.349 grams 1 fluid ounce = 29.574 mL so to go from grams/cm 3 to dry ounces per fluid ounce, multiply by 0.9586.

5 0

3 years ago

Anemia _____.

Andrews [41]

$Answer ☘️$

can be prevented by eating iron-rich foods

Hope it helps ~

5 0

2 years ago

A 100. 0 ml sample of 0. 10 m nh3 is titrated with 0. 10 m hno3. Determine the ph of the solution after the addition of 100. 0 m

DerKrebs [107]

The pH of the solution after the addition of 100. 0 ml of HNO3. The kb of NH3 is 1. 8 × 10-5. So, pH is 10.9 basic .

This neutralization occurs as the acid is added to the base:

NH3(aq)+ HNO3(aq)= NH4NO3(aq)+ H2O(l)

The initial moles of NH3present is given by,

nNH3= c×v= 0.10× 100/1000= 0.01m

The number of moles of

HNO3 added is given by:

nHNO3= c×v= 0.10× 100/1000= 0.001

It is clear from the equation that the acid and base react in a 1:1 molar ratio. So, the no. moles of NH3remaining will be 0.01 - 0.001= 0.009

The total volume is now

100.0+100.0= 200.0x cm3

The concentration of NH3 is given by,

[NH3]= c/v= 0.001/200/1000= 0.05x mol/l .

pOH= 12 (pKb− logb)

where b is the base's concentration.

Given that there is little dissociation, we can roughly compare this to the starting concentration.

pKb= −logKb= −log(1.8×10−5)= 4.744

pOH= 3.056

At 25∘xC, we know that, pH+ pOH=14

pH= 14− 3.056= 10.9

To know more about Equilbrium, visit-brainly.com/question/14366127

#SPJ4

8 0

2 years ago