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vazorg [7]
4 years ago
6

You run at a rate of 4 mph and your friend runs at a rate of 3.5 mph Your friend starts running 10 minutes before you, and you b

oth run for a half an hour on the same path.
A. Find your speed and your friends speed in miles per minute

B. Will you catch up with your friend by the time your friend stops running?
Mathematics
1 answer:
irga5000 [103]4 years ago
5 0

Answer:

A)

<u>i) Your speed: 0.067 miles per minute</u>

<u>ii) Your friend's speed: 0.058 miles per minute</u>

<u>B) You will not catch up with your friend by the time your friend stops running.</u>

Explanation:

<u>A. Find your speed and your friend's speed in miles per minute</u>

<u>i) Your speed:</u>

You know your speed is 4 mph, which is 4 miles per hour. To find you spedd in miles per minute you must multiply by the factor that relates hours and minutes:

  • 1 hour = 60 min

  • 1 = 1 hour / 60 min

  • 4 miles / hour × 1 hour / 60 min = 4 miles / 60 min ≈ 0.0667 miles/min

         (note that the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>ii) Your friend's speed</u>

  • 3.5 miles / hour × 1 hour / 60 min = 3.5 miles / 60 min ≈ 0.0583 miles / min.

(again, the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>B. Will you catch up with your friend by the time your friend stops running?</u>

To find whether you catch up your friend you can use a system of equation that relates the times and the distances run by each one.

i) The distance run by you is equal to your time times your speed:

  • d₁ = 0.0667 miles / min × t₁

ii) The distance run by your friend is equal to his time times his speed.

  • d₂ = 0.0583 miles / min × t₂

Since you friend started running 10 minutes before you, his time is 10 minutes more than yours, i.e. t₂ = 10 min + t₁.

Now you can write the second equation as:

  • d₂ = 0.0583 miles / min × (10 min + t₁).

And since you want to determine whether you catch up him/her by the time he/she stops running, you can determine the time when both distances would be equal:

  • d₁ = d₂

  • 0.0667 miles / min × t₁ = 0.0583 miles / min × (10 min + t₁)

To solve the equation I will ignore the units (normal procedure to solve equations):

  • 0.0667 t₁ = 0.0583 (10 + t₁)

  • 0.0667 t₁ = 0.583 + 0.0583t₁

  • 0.0667 t₁ - 0.0583 t₁ = 0.583

  • 0.0084 t₁ = 0.583

  • t₁ = 0.583 / 0.0084 ≈ 69 min

That is the time you need to catch up your friend, 69 min. Since your friend started 10 min before you and will stop after half an hour (30 min), you will not catch up with your friend before the time your friend stops running.

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Answer:

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Step-by-step explanation:

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... LM = (38 +78)/2 = 116/2 = 58

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Annette [7]

Using the relation between velocity, distance and time, it is found that the commute took 48 minutes.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is distance divided by time, that is:

v = \frac{d}{t}

For Lena, we have that d = 29, v = 36, hence the time in hours is given by:

t = \frac{d}{v} = \frac{29}{36} = 0.8056

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Paul [167]

Answer:

a + b = 5

Step-by-step explanation:

To solve this system of equations, we can use a strategy called elimination, which is when we get rid of a variable by adding/subtracting two equations.

Firstly, we want to make sure the absolute value of the coefficients that equal.

Lets eliminate b:

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Multiply both sides by 2:

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We also have:

6a - 12b = -6.

Now lets add that with

8a + 12b = 48

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Now that we know a, lets plug it into one of our original equations:

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Finally, add the two values we found:

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Mr. Gengel wants to make a shelf with boards that are 1 1/3 feet long. If he has an 18-foot board, how many pieces can he cut fr
irina1246 [14]

Answer:

13

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